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TEA [102]
3 years ago
5

Mrs. Preston had 513 leaves. She gave 274 leaves to her students. Draw to show how you found your answer. How many leaves does s

he still have?
Mathematics
2 answers:
Oksanka [162]3 years ago
7 0
513-274=239
She has 239 leaves left.
oksian1 [2.3K]3 years ago
7 0
250 is the right answer
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Solve the compound inequality: 3x ≤ 18 AND x + 4 > 2
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There must be a mistake in your question:
If 3 x ≤ 9, then : x ≤ 3  and : 
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x > 2 - 4
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Answer: D) 
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Step-by-step explanation:

If you write it out it will look like this 8 1/2÷1 7/10

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because of maths you have to turn 17/10 into 10/17

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Step-by-step explanation:

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3 years ago
911 x 65 what is 911 x 65 not just the answer the work to
alexandr402 [8]

Answer:

Step-by-step explanation:

911

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4 years ago
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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

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<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

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3 years ago
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