Does anyone know the answer for this
1 answer:
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Explanation:
As density is defined as the mass of a substance divided by its volume.
Mathematically, Density =
It is given that mass is 50 g and density is 0.934 .
Hence, calculate the volume of methyl acetate as follows.
Density =
0.934 =
Volume =
or, = (as 1
= 1 mL)
Thus, we can conclude that the volume of methyl acetate the student should pour out is .
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%