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liubo4ka [24]
3 years ago
14

Your mobile charger is an example ofa.transformerb.solenoidc.motor.d.generator​

Physics
2 answers:
lianna [129]3 years ago
5 0

Answer:

Your mobile charger is an example of (d.) a generator.

Explanation:

Your mobile charger generates energy to charge your device.

erastovalidia [21]3 years ago
4 0

Answer:

Generator

Explanation:

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Add 1299 g and 45.1 kg and express your answer in milligrams (mg) to the correct number of significant figures. A) 4.64 x 10t mg
Triss [41]

Answer: 4.64 × 10^7 mg

Explanation:

Given:

T =1299g + 45.1kg

Convert kg to g

T = 1299g + 45.1kg ×1000g/kg

T = 1299g + 45100g

T = 46399g

T= 4.64 × 10^4 g

Convert to milligram

T = 4.64 × 10^4 g × 1000mg/g

T = 4.64 × 10^7 mg

Therefore, 1299g + 45.1kg = 4.64 × 10^7 mg

4 0
3 years ago
A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevat
WINSTONCH [101]

Answer:

The magnitude of the acceleration of the elevator is 0.422 m/s²

Explanation:

Lets explain how to solve the problem

Due to Newton's Law ∑ Forces in direction of motion is equal to mass

multiplied by the acceleration

We have here two forces 460 N in direction of motion and the weight

of the person in opposite direction of motion

The weight of the person is his mass multiplied by the acceleration of

gravity

→ W = mg , where m is the mass and g is the acceleration of gravity

→ m = 45 kg and g = 9.8 m/s²

Substitute these values in the rule above

→ W = 45 × 9.8 = 441 N

The scale reads 460 N

→ F = 460 N , W = 441 N , m = 45 kg

→ F - W = ma

→ 460 - 441 = 45 a

→ 19 = 45 a

Divide both sides by 45

→ a = 0.422 m/s²

<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>

4 0
4 years ago
An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

L = 143 km

I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

Finally,

I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
In a mixture the original substances change to form a new substance.<br> A. True<br><br> B. False
lbvjy [14]
A. True hope this helps
7 0
3 years ago
According to Hess’s theory, what might happen if the magma under a mid-ocean ridge cools? The magnetic stripes might reverse dir
Margarita [4]

Answer:

The magnetic stripes might reverse direction. The deep-ocean trench might become deeper.

Explanation:

mark me brainliest! pls

5 0
2 years ago
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