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3 years ago

List the two factors used to calculate force ? (20 pionts)

Chemistry

2 answers:

Yuliya22 [10]3 years ago

5 0

Answer:The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other.

Explanation: i hope it answers your question

viva [34]3 years ago

5 0

Answer:

blah blah blah

Explanation:

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What are the reactants in the following equation; NaOH + HCI --> NaCl + H2O

choli [55]

The reactants are a) NaOh and HCl because they are on the left side of the equation/arrow :)

7 0

3 years ago

Quick electron emissions are called

vivado [14]

Answer:

Beta decay

Quick electron emissions are called beta decay

Hope this helps

5 0

3 years ago

To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate i

enyata [817]

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

$0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol$

Thus there are 0.00269 moles of acetic acid in buffer.

8 0

3 years ago

Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t

solniwko [45]

Heart: Pumps blood through the body
Bone: Provides structure
Stomach: Breaks down food into small particles
Lungs: Oxygenates blood

7 0

3 years ago

Read 2 more answers

A gas has a volume of 50.0 cm3 at a temperature of -73°c. what volume would the gas occupy at a temperature of -123°c if the pre

vaieri [72.5K]

Boyle’s Law illustrates the inverse relationship of volume and pressure. It follows the formula p1V1 = P2V2 , where P1V1 denotes initial pressure and volume and P2V2 denotes values of pressure and volume.

Now, let us work out for what is asked above.
a. if the pressure is doubled
50.0 p = V x 2p
V = 50.0 p / 2p

= 50.0 /2

= 25.0 m^3
b. if the pressure is cut in half
50.0 p = V x p/2
100 p = V x p
V = 100 m^3
c. if the pressure is tripled
50.0 p = V x 3p
V = 50.0 p / 3p

= 50.0 /3

=16.7 m^3

7 0

3 years ago