Yes , CH3OH - this is methanol
Answer :
(a) The rate of
formed is, 0.066 M/s
(b) The rate of
formed is, 0.033 M/s
Explanation : Given,
= 0.066 M/s
The balanced chemical reaction is,

The rate of disappearance of
= ![-\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
The rate of disappearance of
= ![-\frac{d[O_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
The rate of formation of
= ![\frac{1}{2}\frac{d[NO_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D)
As we know that,
= 0.066 M/s
(a) Now we have to determine the rate of
formed.
![\frac{1}{2}\frac{d[NO_2]}{dt}=\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
![\frac{d[NO_2]}{dt}=\frac{d[NO]}{dt}=0.066M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D%3D0.066M%2Fs)
The rate of
formed is, 0.066 M/s
(b) Now we have to determine the rate of molecular oxygen reacting.
![-\frac{d[O_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BNO%5D%7D%7Bdt%7D)
![\frac{d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.066M%2Fs%3D0.033M%2Fs)
The rate of
formed is, 0.033 M/s
Answer:
because of accumulation of lactic acid due to anaerobic respiration