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Liono4ka [1.6K]
3 years ago
14

Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t

he body Both breaks down food into small particles Both oxygenates blood
Chemistry
2 answers:
solniwko [45]3 years ago
7 0
Heart: Pumps blood through the body
Bone: Provides structure
Stomach: Breaks down food into small particles
Lungs: Oxygenates blood
pav-90 [236]3 years ago
3 0

Answer:

Heart: Pumps blood through the body

Bone: Provides structure  for the body

Stomach: Breaks down food into small particles

Lungs: Oxygenates blood

Explanation:

Heart pumps oxygenated blood through the arteries to various parts of the body.

Bones make up the skeletal system which provides structure to the body.

Stomach has various digestive enzymes and HCl to break down food.

We breather in oxygen though the lungs. Oxygen combines with hemoglobin to oxygenate blood.

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How many moles of MgCl2 are there in 342 g of the compound?
Zanzabum

Answer:

There are  342 g/ 95. 2 g/m = 3.59 moles

Explanation:

MgCl2 → Molar mass is 95.2g g/m

This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.

342 g/ 95. 2 g/m = 3.59 moles

4 0
3 years ago
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If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

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Explanation:

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=

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1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

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Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

⇒

V

2

=

V

1

⋅

T

2

T

1

=

60

⋅

273

546

=

60

2

=

30

l

i

t

e

r

⇒

V

2

=

30

l

i

t

e

r

Hence the new volume of the gas is

30

l

i

t

e

r

6 0
3 years ago
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SCORPION-xisa [38]
222.5 g

I did it like this:

X/250= 89/100=
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4 0
3 years ago
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Nitrogen-7 configuration
11Alexandr11 [23.1K]

Explanation:

Electronic configuration of Nitrogen -

₇N = 1s² 2s² 2p³

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