Two charges repel one another. What must be the case?

A container of gas is at a pressure of 3.7 × 105 Pa How much work is done by the gas if its volume expands by 1.6 m3?

cupoosta [38]

Answer:

Work is done by the gas = 5.92 x 10⁵ J = 592 kJ

Explanation:

Work done at fixed pressure, W = PΔV

Pressure, P = 3.7 x 10⁵ Pa

Change in volume, ΔV = 1.6 m³

Substituting the values of pressure and change in volume we will get

Work done at fixed pressure, W = PΔV = 3.7 x 10⁵ x 1.6 = 5.92 x 10⁵ J

Work is done by the gas = 5.92 x 10⁵ J = 592 kJ

5 0

3 years ago

Whats the difference between being a christian and being a drug addict..?

tangare [24]

There is a huge diffrenc like one is following christ the other is bringing the devil to pepole

5 0

3 years ago

Read 2 more answers

a projectile whose masss is 10g is fired directly upward from ground level with an initial velocity of 1000m/s neglecting the ef

sammy [17]

Answer:

<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>

Explanation:

<u>Vertical Launch</u>

When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.

The speed when the object is moving upwards is given by

$v_f=v_o-g.t$

The time it takes to reach the maximum height is when vf=0, i.e.

$0=v_o-g.t$

solving for t

$\displaystyle t=\frac{v_o}{g}$

The maximum height reached is

$\displaystyle y=\frac{gt^2}{2}=\frac{v_o^2}{2g}$

Then, the object starts to fall. The object's height is given by

$\displaystyle y=\frac{v_o^2}{2g}-\frac{gt'^2}{2}$

where t' is the time the object has traveled downwards. The height will be 0 again when

$\displaystyle \frac{v_o^2}{2g}=\frac{gt'^2}{2}$

Solving for t'

$\displaystyle t'=\frac{v_o}{g}$

We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is

$v_f=g.t'=v_o$

Thus, the speed of the projectile when it impacts the ground is 1000 m/s

4 0

4 years ago

Which of the following are advantages of the SI system?

saul85 [17]

Answer:

A is the answer

Explanation:

That's why it ranges from big to small.

6 0

3 years ago

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Why is the voltage of the supply decreased before entering our homes ?

Reptile [31]

Answer:

After power is generated at a power plant, its voltage is increased by a step-up transformer. The power then travels through transmission lines to a neighborhood where it will run homes, offices, and factories. But before entering the neighborhood, the power's voltage is decreased by a step-down transformer

Transformers can be used either to increase the voltage (called "stepping up") or decrease the voltage ("step down"). When electrical energy travels long distances in wires, some of the energy is lost. ... Later, the voltage is stepped down before it enters your home - once again using transformers

3 0

3 years ago