A mineral consisted of 29.4% calcium, 23.5% sulfur and 47.1% oxygen. What is the empirical formula?

1 answer:

5 0

Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol

moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles

calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4

You might be interested in

Which is a spectator ion in the reaction between NaOH(aq) and H2SO4(aq)?

melisa1 [442]

The reaction between NaOH and H2SO4 is a reaction between an acid and a base which means the reaction is a neutralization that produces products of salt and water. The salt is Na2SO4.
spectator ions are ions that are found at the both sides of the equation when the aqueous components are in their ionic forms. In this case, when breaking down of components is applied, the spectator ions are Na + and SO4 2- .

8 0

3 years ago

Read 2 more answers

Write a balanced net ionic equation for the following reaction. Explain how you arrived at this answer. What did you cancel out?

Alex787 [66]

The net ionic equation is

Ag⁺(aq) +Cl⁻(aq) → AgCl(s)

<u><em>Explanation</em></u>

AgNO₃ (aq) + KCl (aq)→ AgCl(s) +KNO₃(aq)

from above molecular equation break all soluble electrolyte into ions

Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) → AgCl (s) + K⁺(aq) + No₃⁻(aq)

cancel the spectator ions in both side of equation =K⁺ and NO₃⁻ ions