Answer:
23dm
Explanation:
so you have to do 10g +13dm so the you have to times it by 3 three times
Refer to the diagram shown below.
The piston supports the same load W at both temperatures.
The ideal gas law is

where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant
State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter
State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter
Because V, n, and R remain the same between the two temperatures, therefore

If the supported load is W kg, then

Similarly,


Because p₁/p₂ = T₁/T₂, therefore

The minimum piston diameter at 150 C is 20.8 cm.
Answer: 20.8 cm diameter
Answer:
81.54 °C
Explanation:
Use the equation
q = mcΔT
348 = 20.9(0.902)(100-t)
t = 81.54 °C
*note, you don't have to convert these to kelvin since the difference will be the same
Answer:
526.85K
Explanation:
Based on Charles's law, the volume of a gas is directly proportional to absolute temperature. The formrula is:
V₁ / T₁ = V₂ / T₂
<em>Where 1 represents the initial state and 2 the final state of the gas</em>
Using the values of the problem:
V₁ = 10.0L
T₁ = 127°C + 273.15K = 400.15K
V₂ = 20.0L
Thus, replacing in the formula:
10.0L / 400.15K = 20.0L / T₂
T₂ = 800K
In Celsius:
800K - 273.15 =<em> 526.85K</em>
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