A compound with the formula C6H12 is not considered a Saturated hydrocarbon.
Why is C6H12 isn't considered a Saturated hydrocarbon?
The ring's presence demonstrates that it is unsaturated. Keep in mind that the general formula for aliphatic hydrocarbons, CnH2n+2, serves as the foundation for its saturation. A chemical is unsaturated if it does not meet this requirement.
Example:
Hexane (C6H14)
C = 6; H = 14 = 2(6) + 2
resulting in hexane becoming saturated.
Cyclohexane(C6H12)
C = 6 and H = 12 do not equal 14 (x)!
cyclohexane is an unsaturated molecule as a result.
Cycloalkanes have the general formula C2H2n as well.
Hence, the given statement is false.
Learn more about the hydrocarbons here,
brainly.com/question/17578846
# SPJ4
Isotopes= a group of atoms with the same no. of protons , but different no. of neutrons
Hydrogen isotopes
The name of the second isotope is deuterium and the name of the third isotope is tritium(radioactive).The most abundant isotope is
Answer:
The definition of physical science is the sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects.
Explanation:
Answer:
Michaelis constant is known as km which is the substrate concentration that encourages the compound to work at half maximum velocity represented by Vmax/2. Michaelis constant is inversely related to the substrate and the affinity of the enzyme.
Induced fit model: The premise of the purported induced fit hypothesis, which expresses that the attachment or association of a substrate or some other atom to an enzyme causes an adjustment to the enzyme in order to fit or restrain its activity.
In substrate, analog Km or Michaelis constant will be high as the substrate will stay because of analogs inhibit activity.
In the transitional state, analog Km will be in the middle of the substrate and product analogs. Progress state analogs are synthetic mixes with a structure catalyzed reaction that looks like the progressing condition of a substrate atom in a compound enzyme.
In item simple thus Km is the least.
0.0013 M = product ananlog,
0.025 M=Transition state, and
0.0045 M = Substrate analog
Answer:
0.053moles
Explanation:
Hello,
To calculate the number of moles of gas remaining in his after he exhale, we'll have to use Avogadro's law which states that the volume of a given mass of gas is directly proportional to its number of moles provided that temperature and pressure are kept constant. Mathematically,
V = kN, k = V / N
V1 / N1 = V2 / N2= V3 / N3 = Vx / Nx
V1 = 1.7L
N1 = 0.070mol
V2 = 1.3L
N2 = ?
From the above equation,
V1 / N1 = V2 / N2
Make N2 the subject of formula
N2 = (N1 × V2) / V1
N2 = (0.07 × 1.3) / 1.7
N2 = 0.053mol
The number of moles of gas in his lungs when he exhale is 0.053 moles
