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Anestetic [448]
3 years ago
5

When MgCl2 dissolve in water does the Mg and Cl split apart?

Chemistry
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

Yes they do,

Explanation:

The spitting is called dissociation

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Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!
e-lub [12.9K]
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol


Find the molar mass
2Na = 23 * 2 = 46 grams
1S   = 32 * 1 = 32 grams
O4   = 16 * 4 = 64 grams
Total =            142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams. 

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L


4 0
3 years ago
Read 2 more answers
Which of the following aqueous solutions has the highest boiling point?A. 1.25 M Ca(NO3)2B. 1.25 M KNO3C. 1.25 M CH3OHD. 2.50 M
Drupady [299]

Answer:

Ca(NO3)2 has the highest boiling point ( option A)

Explanation:

Step 1: Data given

A. 1.25 M Ca(NO3)2

B. 1.25 M KNO3

C. 1.25 M CH3OH

D. 2.50 M C6H12O6

Step 2: Calculate highest boiling point

The boiling point depends on the van't Hoff factor

This shows the particles produced when the substance is dissolved. For non-electrolytes dissolved in water, the van' t Hoff factor is 1.

Ca(NO3)2 → Ca^2+ + 2NO3- → Van't Hoff factor = 3

KNO3 → K+ + NO3- → Van't Hoff factor = 2

CH3OH is a non-elektrolyte → Van't Hoff factor = 1

C6H12O6 is a non-elektrolyte → Van't Hoff factor = 1

Ca(NO3)2 has the highest boiling point

5 0
3 years ago
A negatively charged ion that is formed by an atom gaining one or more electrons is called a(n):
Vilka [71]

Answer:

"Anion" is correct option

Explanation:

An anion is an ion that has gained one or more electrons, acquiring a negative charge.

8 0
3 years ago
Read 2 more answers
Hemoglobin molecules in blood bind oxygen and carry it to cells, where it takes part in metabolism. The binding of oxygen hemogl
Alex73 [517]

Without wasting much of our time, Here is the correct question.

Hemoglobin molecules in blood bind oxygen and carry it to cells, where it takes part in metabolism. The binding of oxygen hemoglobin(aq) + O2(aq) -------> hemoglobin O2(aq) is first order in hemoglobin and first order in dissolved oxygen, with a rate constant of 4 × 10⁷ L mol⁻¹ s⁻¹. Calculate the initial rate at which oxygen will be bound to hemoglobin if the concentration of hemoglobin is 2 × 10⁻⁹ M and that of oxygen is 5 × 10⁻⁵M.

Answer:

4 × 10⁻⁶ M s⁻¹

Explanation:

The equation for the reaction between Hemoglobin molecules in blood that binds with oxygen molecule can be represent by:

hemoglobin_{(aq)  +  O_{2(aq)   ---------> hemoglobin.O_{2(aq)

Now, we are also being told to calculate only!, the  initial rate at which oxygen will be bound to hemoglobin.

So, If it is first order in hemoglobin and also first order in Oxygen molecule at the initial rate of the the reaction, therefore, the rate  for the reaction can be expressed as :

rate = k [hemoglobin_{(aq)}][O_{2(aq)}]

Let's not forget that we are so given some parameters;

where

k (rate constant) = 4 × 10⁷ L mol⁻¹ s⁻¹

[ hemoglobin_{(aq) ] = 2 × 10⁻⁹ M

[  O_{2(aq)  ]  =  5 × 10⁻⁵ M

Substituting our data given into the above rate formula, we have:

rate = (4 × 10⁷ L mol⁻¹ s⁻¹) × (2 × 10⁻⁹ M) × (5 × 10⁻⁵ M)

rate = 4 × 10⁻⁶ M s⁻¹     ( given that 1 M = 1 mol L⁻¹ )

∴ the initial rate at which oxygen will be bound to hemoglobin = 4 × 10⁻⁶ M s⁻¹

7 0
3 years ago
Read the given chemical reaction.
k0ka [10]
It is d
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6 0
3 years ago
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