The answer is B. is the energy source of stars.
Fission is the type of nuclear energy simulated on Earth, as it is the one used to generate electricity. Fusion, on the other hand, is much more complicated to achieve because it requires extremely hot temperatures compared to fission. Fusion involves the combination of two hydrogen atoms to make helium, which releases a lot of energy. Stars such as the sun, exhibit fusion with its very hot temperature and abundant source of hydrogen.
The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅
<h3>How do I determine the formula of the compound?</h3>
From the question given above, the following data were obatined:
- Sulphur (S) = 8.6 moles
- Phosphorus (P) = 3.42 mole
- Chemical formula =?
The chemical formula of the compound can be obtained as follow:
Divide by their molar mass
S = 8.6 / 32 = 0.26875
P = 3.42 / 31 = 0.11032
Divide by the smallest
S = 0.26875 / 0.11032 = 2.44
P = 0.11032 / 0.11032 = 1
Multiply by 2 to express in whole number
S = 2.44 × 2 = 5
P = 1 × 2 = 2
Thus, the chemical formula is P₂S₅
Learn more about empirical formula:
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Explanation:
a) In 1 mole of methane there are 4 moles of hydrogen atom
Atomic mass of 1 mole of hydrogen atom = 1 g
Mass of hydrogen in 1 mole of methane = 4 × 1 g = 4 g
b) In 1 mole of chloroform there are 1 mole of hydrogen atom
Atomic mass of 1 mole of hydrogen atom = 1 g
Mass of hydrogen in 1 mole of methane = 1× 1 g = 1 g
c) In 1 mole of 
there are 10 moles of hydrogen atom
Atomic mass of 1 mole of hydrogen atom = 1 g
Mass of hydrogen in 1 mole of = 10 × 1 g = 10 g
d)In 1 mole of 
there are 12 moles of hydrogen atom.
Atomic mass of 1 mole of hydrogen atom = 1 g
Mass of hydrogen in 1 mole of = 12 × 1 g = 12 g
Food handler be unsuccessful to wash hands correctly after spending the restroom or when their hands become dirty.
Food handler coughs or sneezes on foodstuff.
Food handler traces or scratches wounds, cuts, or sores, and then touches food.
Food handler works though sick.
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The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
