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2 years ago

what is the reason for the difference between the values of the dry adiabatic lapse rate and the moist adiabatic lapse rate?

1 answer:

6 0

Latent heat released during condensation offsets some of the cooling of a rising air parcel, causing the moist adiabatic lapse rate to have a smaller value.

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Density is the ratio of mass to volume. Another way to say this is

Oliga [24]

Answer:

my teacher would let u say the density to mass is the ratio but i think everyone's different

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2 years ago

What was Anton van Lee

solniwko [45]

I would say the answer is A.

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2 years ago

A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How

Irina-Kira [14]

<h3>Answer:</h3>

0.10 L

<h3>Explanation:</h3>

The concentration of glucose is given as 180 g/L

The mass of glucose is 18 g

Concentration in g/L is calculated by dividing mass of the solute by the volume of the solution.
When calculating molarity on the other hand, we divide number of moles of the solute by the volume of the solution.

Concentration in g/L = Mass of solute ÷ Volume

Rearranging the formula,

Volume = Mass of the solute ÷ concentration

= 18 g ÷ 180 g/L

= 0.10 L

Therefore, volume of water is 0.10 L

6 0

3 years ago

What is the percent composition by mass of hydrogen in nh4hco3

Simora [160]

<u>Answer:</u> The percent composition by mass of hydrogen in given compound is 6.33 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of $NH_4HCO_3$

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

$\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100$

Mass of compound = $[(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol$

Mass of hydrogen = $(5\times 1)=5g/mol$

Putting values in above equation, we get:

$\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%$

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0

3 years ago

PLEASE ANSWER AS SOON AS POSSIBLE! 25 Pts

vovikov84 [41]

Um Is there a picture :/

8 0

2 years ago