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Inga [223]
3 years ago
8

A person wears a hearing aid that uniformly increases the sound level of all audible frequencies of sound by 28.1 dB. The hearin

g aid picks up sound having a frequency of 250 Hz at an intensity of 3.30 10-11 W/m2. What is the intensity delivered to the eardrum?
Physics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

 I₂ = 2.13 x 10⁻⁸ W/m²

Explanation:

given,

increase in sound level = 28.1 dB

frequency of the sound = 250 Hz

intensity = 3.3 x 10⁻¹¹ W/m²

Intensity delivered = ?

the difference of intensity level is give as

\beta_2-\beta_1 = 10log(\dfrac{I_2}{I_o}) - 10log(\dfrac{I_1}{I_o})

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_o}) -log(\dfrac{I_1}{I_o}))

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_1})

28.1= 10(log(\dfrac{I_2}{I_1})

log\dfrac{I_2}{I_1}=2.81

\dfrac{I_2}{I_1}=10^{2.81}

 I₂ = 645.65 I₁

 I₂ = 645.65 x 3.3 x 10⁻¹¹

 I₂ = 2.13 x 10⁻⁸ W/m²

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