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inysia [295]
3 years ago
13

Which of the following is a CHEMICAL factor affecting marine biomes?

Physics
1 answer:
evablogger [386]3 years ago
6 0

Answer:

pH

Explanation:

pH is the only chemical which is an acid that affects marine biomes, if there is too much acidity in the water (pH) then the marine life will die.

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2.5 x 103 kilogram truck with rubber tires moves through a 120 meter radius turn on a dry asphalt surface.
just olya [345]

Answer:

a. The friction force acting on the truck's tires during the turn, is approximately 20,875 N

b. The maximum velocity with which the truck could make the bend is approximately 31.654 m/s

Explanation:

The given parameters of the truck are;

The mass of the truck, m = 2.5 × 10³ kg

The tire material = Rubber

The radius of the turn the through which the truck moves = 120 meters

The material and condition of the surface = Dry asphalt

a. The coefficient of friction of rubber tires on dry asphalt, μ ≈ 0.85 (researchgate (internet source))

The weight of the truck, W = m × g

Where;

m = The mass of the truck = 2.5 × 10³ kg

g = The acceleration due to gravity = 9.8 m/s²

∴ W = 2.5 × 10³ kg × 9.8 m/s² = 24,500 N

The force of friction acting on the tires, F_f = W × μ

∴ F_f = 24,500 N × 0.85 ≈ 20,875 N

The friction force acting on the truck's tires during the turn, F_f ≈ 20,875 N

b. The centrifugal force the truck observes while turning through the bend, 'F', is given as follows;

F = m·v²/r

Therefore, the maximum velocity with which the truck could make the bend, 'v', is given when fiction force, 'F_f', is equal to the centripetal force, F

When F_f = F, we have;

W × μ = m·v²/r

∴ 20,875 N = 2.5 × 10³ kg × v²/(120 m)

∴ v² = 20,875 N × (120 m)/(2.5 × 10^3 kg) = 1002 m²/s²

v = √(1002 m²/s²) ≈ 31.654 m/s

The maximum velocity with which the truck could make the bend, v ≈ 31.654 m/s

8 0
3 years ago
A 3000-kg truck moving with a velocity of 25 m/s hits a 1000-kg parked car. The impact causes the 1000-kg car to be set in motio
Alborosie

Answer:

v₃ = 22.67 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the quantity of linear momentum. Where momentum is conserved before and after the collision, i.e. remains the same.

The terms on the left of the equation represent the amount of linear momentum before the collision and the members on the right represent the momentum after the collision.

(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}*v_{3})+(m_{2}*v_{4})

where:

m₁ = mass of the truck = 3000 [kg]

m₂ = mass of the car = 1000 [kg]

v₁ = velocity of the truck before the coliision = 25 [m/s]

v₂ = velocity of the car parked = 0 (without movement)

v₃ = velocity of the truck after the collision [m/s]

v₄ = velocity of the car after the collision = 7 [m/s]

Now replacing:

(3000*25)+(1000*0)=(3000*v_{3})+(1000*7)\\75000-7000 = 3000*v_{3}\\v_{3}=22.67 [m/s]

4 0
3 years ago
What is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s?
romanna [79]
K=1/2(mass)(velocity)^2
Mass=1.0
Velocity=5.0
K=1/2(1)(5)^2
K=12.5 J 
3 0
3 years ago
How is 0.00069 written in scienitfic notation?
victus00 [196]
You need to move the decimal point between the six and nine. 6.9 X 10^-4
8 0
3 years ago
The PVT behavior of a certain gas is described by the equation of state: P(V − b) = RT where b is a constant. If in addition CV
alexdok [17]

Answer:

shown in the attachment

Explanation:

The detailed step by step and necessary mathematical application is as shown in the attachment.

6 0
3 years ago
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