Answer:
Explanation:
Let v is the launch speed of the plastic ball and the angle of projection is θ.
So, in horizontal direction
v Cosθ x t = 4.8 .... (1)
In th evertical direction
1.4 = v Sin θ x t - 0.5 gt² .... (2)
As , v Sin θ x t = 3.8 .... (3) , put in equation (2)
1.4 = 3.8 - 4.9 t²
t = 0.7 s
Put in (1) and (3)
v Cosθ x 0.7 = 4.8
v Cosθ = 6.86
and v Sinθ x 0.7 = 3.8
v Sinθ = 5.43
Now
v = 8.75 m/s
Answer:
AI
Explanation:
it stands for artificial intelligents
The answer is Helium Flash.
A helium flash marks the looming end of a red giant. As a red giant expands in its outer layers, its core is actually contracting. The core would eventually form a white dwarf.
As the core reaches a certain temperature, helium will start to fuse to form carbon. As this occurs, the fusing of helium, the core heats up. The core is not able to expand to cool down, so the reaction increases the core until the core will ultimately explode.
<span>Batteries provide a voltage difference.</span>
Answer:
A) The work done by the engine is: 6.8MJ/L
B) The fuel efficiency is
Explanation:
A)
We know that the gasoline releases about 3.4*10^7 J of energy for each liter, and about 80% of that energy is lost as heat; it means that the other 20% of the energy released is taken for the engine to do work. In that sense, the work done by the engine is 20% of the 3.4*10^7 J that the gasoline releases for 1 liter, so:
This last can be seen as a conversion factor, where we multiply the energy released by the gasoline by the factor (20 J taken for do work for each 100 J released).
B) We know that the car requires 5.9*10^5 J of work <u>for each km traveled</u>. That is the energy that the car requires, but it is not the energy that you have to give to the car; take in mind that the energy that you put in the car in gasoline liters will be not taken all, but just 20%. Also we know that the work done by the engine for 1 liter of gasoline is 6.8MJ, and that is just the work taken for do work (the useful energy), so we can connect both data:
The first fraction, is the ratio or the proportion of (1 km requieres 5.9*10^5 J); and we multiply by the second fraction , which is the ratio: 6.8*10^6 J of work done for each liter of gasoline.