Answer:


Explanation:
Given:
- flow rate of water,

<em>∵Density of water is 1 kg per liter</em>
∴mass flow rate of water, 
- height of pumping,

- efficiency of motor drive,

- diameter of pipe,

<u>Now the power required for pumping the water at given conditions:</u>



<u>Hence the electric power required:</u>



<u>Flow velocity is given as:</u>

where: a = cross sectional area of flow through the pipe


Pressure with Height: pressure decreases with incrementing altitude. The pressure at any caliber in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a homogeneous surface at lower calibers.
We have vector 
Therefore,
x component = 17.9 * cos80 degree = 3.108
y component = 17.9 * sin80 degrees = 17.628
<h3>What is a vector?</h3>
An object with both magnitude and direction is referred to be a vector. A vector can be visualized geometrically as a directed line segment, with an arrow pointing in the direction and a length equal to the magnitude of the vector. The vector points in a direction from its tail to its head.
If the magnitude and direction of two vectors match, they are the same vector. This shows that if we move a vector to a different location without rotating it, the final vector will be the same as the initial vector. The vectors that denote force and velocity are two examples. The direction of force and velocity are both fixed. The size of the vector would represent the force's strength or the velocity's corresponding speed.
To know more about vectors, visit:
brainly.com/question/12937011
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