Answer:
1) a) I₁ = 0.2941 kg m², b) I₂ = 0.2963 kg m², c) I_{total} = 0.5904 kg m²
3) α = 6.31 10⁶ rad / s²
Explanation:
1) The moment of inertia for bodies with high symmetry is tabulated, for a divo with an axis passing through its center is
I = ½ m r²
a) moment of inertia of the upper disk
I₁ = ½ m₁ r₁²
I₁ = ½ 1,468 0.633²
I₁ = 0.2941 kg m²
b) upper aluminum disc moment of inertia
I₂ = ½ m₂ r₂²
I₂ = ½ 1.479 0.633²
I₂ = 0.2963 kg m²
c) the moment of inertia is an additive scalar quantity therefore
I_{total} = I₁ + I₂
I_{total} = 0.2941 + 0.2963
I_{total} = 0.5904 kg m²
3) ask the value of the angular acceleration, that is, the second derivative of the angle with respect to time squared
indicate the angular velocity of the system w = 400 rev / s
Let's reduce the SI system
w = 400 rev / s (2π rad / rev) = 2513.27 rad / s
as the system is rotating we can calculate the centripetal acceleration
a = w² R
a = 2513.27² 0.633
a = 3.998 10⁶ m / s²
the linear and angular variable are related
a = α r
α = a / r
α = 3.998 10⁶ / 0.633
α = 6.31 10⁶ rad / s²
Answer:
Snell's Law states
Ni sin i = Nr sin r
Judging from the question the source of the ray is in the water (directed up)
or NI = 1 / sin 49 Ni = 1.325 deg the critical angle
From inside the pond:
Nr = 1.325 * sin 45 / 1 = 94 deg
So refraction can occur outside the pond and you do not have total internal refection.
Answer:
1.41s
5.95m/s
0.2746m
Explanation:
The time period
T = 1/f
= 1/0.709s
= 1.41 seconds
We have
T = 2π√l/g
T² = 4π²l/g
g = 4π²l/T²
g = 4x3.14²x0.300/1.41²
g = 5.95m/s² this is the acceleration due to gravity.
Then the time period of the glide
T2 = 2π√m/k
Length of pendulum = l
Time period T
T2 = 2π√l/g
Then T1 = T2
2π√m/k = 2π√l/g
M/k = l/g
L = g.m/k
L = 5.95x0.450/9.75
L = 0.2746
This must be the length of the simple pendulum
Efficiency
Explanation:
Efficiency is a ratio/percentage that is useful in comparing the energy transferred by a device to the total energy supplied to it.
Percentage efficiency = 
x 100
- As with most system, none is 100% efficient.
- During energy is transferred some are lost and only a little portion is used in doing actual work by the machine.
- This validates the third law of thermodynamics which proposes that no system is 100% efficient.
- A 100% efficiency implies total energy input is used doing all the work.
- This is impossible. The bulk of the energy goes into heating the system.
learn more:
Third law of thermodynamics brainly.com/question/3564634
#learnwithBrainly
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