He would try to enter as the tide is rising, and leave as the tide is falling. Those things happen at all different times of day during a month.
M1 v1 = (m1 + m2)v2.
All of the exponents should be lowered to the bottom right of the letters.
Refer to the diagram shown below.
Assume that air resistance is ignored.
Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²
The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²
Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s
The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m
Answer: 319.4 m (nearest tenth)
Answer: not be able to stop in time to miss the object
Explanation:
The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.
When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.
This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.