Ask question

Ask question

All categories

3 years ago

11

If we assume that, in the African savanna, rainfall and the amount of grass is plentiful, what other factor would BEST explain a

reduced antelope population?

2 answers:

valentina_108 [34]3 years ago

8 0

Diseases, Hunting (sport for humans), predators

777dan777 [17]3 years ago

3 0

Increased number of predators

You might be interested in

Figure 1 shows a wave movement during one second. What is the frequency of the wave

Andreyy89

This is 2 hertz. You can mark out 2 full wavelengths in the second of time.

4 0

3 years ago

Read 2 more answers

Does space have plenty of oxygen

xz_007 [3.2K]

Answer:

I don't think so because we can't breathe in space

Explanation:

6 0

2 years ago

Read 2 more answers

A ray diagram shows an object placed between 2F and F of a convex lens.The image produced is

nekit [7.7K]

The image produced is magnified and real.

4 0

3 years ago

Read 2 more answers

A one-piece cylinder has a core section protruding from the larger drum and is free to rotate around its central axis. A rope wr

PilotLPTM [1.2K]

Answer:

Magnitude the net torque about its axis of rotation is 2.41 Nm

Solution:

As per the question:

The radius of the wrapped rope around the drum, r = 1.33 m

Force applied to the right side of the drum, F = 4.35 N

The radius of the rope wrapped around the core, r' = 0.51 m

Force on the cylinder in the downward direction, F' = 6.62 N

Now, the magnitude of the net torque is given by:

$\tau_{net} = \tau + \tau'$

where

$\tau$ = Torque due to Force, F

$\tau'$ = Torque due to Force, F'

$tau = F\times r$

$tau' = F'\times r'$

Now,

$\tau_{net} = - F\times r + F'\times r'$

$\tau_{net} = - 4.35\times 1.33 + 6.62\times 0.51 = - 2.41\ Nm$

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.

Now, the magnitude of the net torque:

$|\tau_{net}| = 2.41\ Nm$

3 0

3 years ago

Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea

Kipish [7]

Answer:

6.5 m/s

Explanation:

We are given that

Distance, s=100 m

Initial speed, u=1.4 m/s

Acceleration, $a=0.20 m/s^2$

We have to find the final velocity at the end of the 100.0 m.

We know that

$v^2-u^2=2as$

Using the formula

$v^2-(1.4)^2=2\times 0.20\times 100$

$v^2-1.96=40$

$v^2=40+1.96$

$v^2=41.96$

$v=\sqrt{41.96}$

$v=6.5 m/s$

Hence, her final velocity at the end of the 100.0 m=6.5 m/s

5 0

2 years ago