Ask question

Ask question

All categories

4 years ago

11

If we assume that, in the African savanna, rainfall and the amount of grass is plentiful, what other factor would BEST explain a

reduced antelope population?

2 answers:

valentina_108 [34]4 years ago

8 0

Diseases, Hunting (sport for humans), predators

777dan777 [17]4 years ago

3 0

Increased number of predators

You might be interested in

How is friction harmful??

gregori [183]

-causes heat; if it's not used correctly, it can cause injury
-when falling, the friction between your knee/leg and the ground can cause scrapes

!!HOPE THIS HELPS!!

4 0

3 years ago

How much more ground motion is produced by an earthquake of magnitude 7.0 than by an earthquake of magnitude 4.0?

beks73 [17]

A hundred times as much ground motion is produced by an magnitude of 7.0 than by a magnitude of 4.0

6 0

4 years ago

What are the similarities between EMS waves and mechanical waves?

irga5000 [103]

Answer:

eternal mangekyou sharingan

Explanation:

4 0

3 years ago

PLS HELP, I AM WILLING TO MARK BRAINLIEST TO FIRST ANSWER AND HAS TOO BE RIGHT

Ann [662]

Weak winds that blow for short periods of time with a short fetch.

6 0

3 years ago

Read 2 more answers

Rutherford discovered the nucleus of the atom by firing a particles at gold foil. An a particle has a charge of q = +2e and a ma

Readme [11.4K]

Answer: $r_0=3.037\times 10^{-14}m$

Explanation:

Given

charge on alpha particle=+2e

mass of alpha particle= $6.64\times 10^{-27}$ kg

Charge on gold nucleus=+79e

Velocity at r=1m is $1.9\times 10^{7}$

Using Energy conservation

Kinetic energy of particle will be converting to Potential energy as it approaches to nucleus

therefore

$\frac{1}{2}mv^2+U_{r=1m}=U_{closest\ to\ nucleus}$

$\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )+\frac{K\left ( 2e\right )\left ( 79e\right )}{1}=\frac{K\left ( 2e\right )\left ( 79e\right )}{r_0}$

$\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )=\frac{9\times 10^9\times 158\times \left ( 1.6\times 10^{-19}\right )}{y}\left [\frac{1}{r_0}-\frac{1}{1}\right ]$

on solving we get

$\frac{1}{r_0}=3.292\times 10^{13}$

$r_0=3.037\times 10^{-14}m$

8 0

3 years ago