Answer:
by using formula F=ma which is m stand for mass a stand for acceleration. so 500kg × 2 ms^-2
a). for velocity, you must have a number, a unit, and a direction.
Yes. This one isn't bad. The 'number' and the 'unit' are the speed.
b). the si units for velocity are miles per hour.
No. That's silly.
'miles' is not an SI unit, and 'miles per hour'
is only a speed, not a velocity.
c). the symbol for velocity is .
You can use any symbol you want for velocity, as long as
you make its meaning very clear, so that everybody knows
what symbol you're using for velocity.
But this choice-c is still wrong, because either it's incomplete,
or else it's using 'space' for velocity, which is a very poor symbol.
d). to calculate velocity, divide the displacement by time.
Yes, that's OK, but you have to remember that the displacement
has a direction, and so does the velocity.
Answer:
Proportional
Explanation:
The conditions that must be met to produce SHM are;
-The restoring force must be proportional to the displacement and act opposite to the direction of motion with no drag forces or friction.
- The frequency of oscillation does not depend on the amplitude.
If i was feeling harsh today, I'd say the answer to your question is impossible to obtain due to the fact that photons do not emit radiation, photons ARE the radiation emitted. Though for the sake of it, here is the method...
<u>The simple method:
</u>
E=hf
therefore f=e/h
f=(3.611x10^-15) / 6.63x10^-34)
Answer: 5.45x10^18
A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to
![F= \frac{GM}{r^2} m](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D%20%20m)
where
![G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2}](https://tex.z-dn.net/?f=G%3D6.67%20%5Ccdot%2010%5E%7B-11%7D%20m%5E3%20Kg%5E%7B-1%7D%20s%5E%7B-2%7D)
is the gravitational constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive.
A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
but since
![F= \frac{GM}{r^2} m](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D%20m)
we can write
![a = \frac{GM}{r^2}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7BGM%7D%7Br%5E2%7D)
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.