Answer:
The human major features with the analogous of camera are mentioned.
Explanation:
There are the following major features of human eye which are analogue with the camera:
- Camera will have shutters which controls light entering into it, human eye consists of Diaphragm which also functions same.
- Both gives Real & inverted images.
- In camera film records image, in eye image is focused on retina and it is converted into electrical impulses.
- Pupil and iris acts as aperture of camera.
Answer:
Explanation:
given data= 34.2 m/s
we have to convert it into km/s
as we know that
1 km=1000 m
so 1 m= 1/1000 =0.001 km
now we know that 1 min=60 sec
so 1 sec=1/60= 0.016 min
therefore
34.2m/s = 34.2*m/sec =34.2*0.001 km /0.016 min
so 34.2 m/s =2.1 km/min
1. ![1.69\cdot 10^{11} m](https://tex.z-dn.net/?f=1.69%5Ccdot%2010%5E%7B11%7D%20m)
The Schwarzschild radius of an object of mass M is given by:
(1)
where
G is the gravitational constant
M is the mass of the object
c is the speed of light
The black hole in the problem has a mass of
![M=5.7\cdot 10^7 M_s](https://tex.z-dn.net/?f=M%3D5.7%5Ccdot%2010%5E7%20M_s)
where
is the solar mass. Substituting,
![M=(5.7\cdot 10^7)(2\cdot 10^{30}kg)=1.14\cdot 10^{38} kg](https://tex.z-dn.net/?f=M%3D%285.7%5Ccdot%2010%5E7%29%282%5Ccdot%2010%5E%7B30%7Dkg%29%3D1.14%5Ccdot%2010%5E%7B38%7D%20kg)
and substituting into eq.(1), we find the Schwarzschild radius of this black hole:
![r_s = \frac{2(6.67\cdot 10^{-11})(1.14\cdot 10^{38} kg)}{(3\cdot 10^8 m/s)^2}=1.69\cdot 10^{11} m](https://tex.z-dn.net/?f=r_s%20%3D%20%5Cfrac%7B2%286.67%5Ccdot%2010%5E%7B-11%7D%29%281.14%5Ccdot%2010%5E%7B38%7D%20kg%29%7D%7B%283%5Ccdot%2010%5E8%20m%2Fs%29%5E2%7D%3D1.69%5Ccdot%2010%5E%7B11%7D%20m)
2) 242.8 solar radii
We are asked to find the radius of the black hole in units of the solar radius.
The solar radius is
![r_S = 6.96\cdot 10^5 km = 6.96\cdot 10^8 m](https://tex.z-dn.net/?f=r_S%20%3D%206.96%5Ccdot%2010%5E5%20km%20%3D%206.96%5Ccdot%2010%5E8%20m)
Therefore, the Schwarzschild radius of the black hole in solar radius units is
![r=\frac{1.69\cdot 10^{11} m}{6.96\cdot 10^8 m}=242.8](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B1.69%5Ccdot%2010%5E%7B11%7D%20m%7D%7B6.96%5Ccdot%2010%5E8%20m%7D%3D242.8)
Answer:
10⁻¹² W / m²
Explanation:
The feeble sound that a man can hear is of the vale which measures 0 on decibel scale . The intensity of sound in terms of J / m² .s is 10⁻¹² W / m² .
So the intensity of sound of monkey at 2.5 km must be 10⁻¹² W / m² .
Answer:
The correct answer is less momentum.
Explanation:
The momentum of an object is directly linked to the force exerted on that object. In a longer barrel, the shot cannonball will have a greater impulse changing to occur a larger momentum and therefore a higher speed will be applied to the bullet, contrary to what would happen in a shorter barrel.