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Alborosie
3 years ago
8

4. A train is travelling at a speed of 60 km/ h. Brakes are applied so as to produce a uniform

Physics
1 answer:
maxonik [38]3 years ago
7 0

Answer:

33.33 m

Explanation:

Applying Newton's equation of motion,

v² = u²+2as...................... Equation 1

Where v = final velocity of the train, u = initial velocity of the train, a = acceleration of the train, s = distance.

make s the subject of the equation

s = (v²-u²)/2a................ Equation 2

Given: v = 0 m/s ( brought to rest), u = 60 km/h = 60(1000/3600) m/s = 16.67 m/s, a = -0.5 m/s²

Substitute this values into equation 2

s = (0-16.67)/-0.5

s = -16.67/-0.5

s = 33.33 m

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2 years ago
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Answer:

2.23 Hz

Explanation:

From the attached diagram below; there exists a diagrammatic representation of the equilibrium position of the cylinder.

The equilibrium position of the spring is expressed as:

mg = K\delta _{st}

where;

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Given that:

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Then;

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From here; let us find the angular velocity which will be needed to determine the natural frequency aftewards.

The angular velocity of the cylinder can be expressed by the formula:

\omega_{n} = \sqrt{\frac{k}{m}}

\omega_{n} = \sqrt{\frac{5886}{30}}

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\omega_{n} = 14.007141 \ \ rad/s

Finally; the natural frequency f_n can be calculated by using the equation

f_n = \frac{\omega_n}{2 \ \pi }

f_n = \frac{14.007141}{2 \ \pi }

f_n= 2.229305729

f_n ≅ 2.23 Hz

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