Answer:
33.33 m
Explanation:
Applying Newton's equation of motion,
v² = u²+2as...................... Equation 1
Where v = final velocity of the train, u = initial velocity of the train, a = acceleration of the train, s = distance.
make s the subject of the equation
s = (v²-u²)/2a................ Equation 2
Given: v = 0 m/s ( brought to rest), u = 60 km/h = 60(1000/3600) m/s = 16.67 m/s, a = -0.5 m/s²
Substitute this values into equation 2
s = (0-16.67)/-0.5
s = -16.67/-0.5
s = 33.33 m
