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Aloiza [94]
2 years ago
13

What does a change in the x value mean when graphing an exponential function?

Mathematics
1 answer:
3241004551 [841]2 years ago
7 0

Answer:

what changes is the exponential function

Step-by-step explanation:

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Can.anyone.help.....
alina1380 [7]

Answer:

0.8

Step-by-step explanation:

4/5 which is 0.8, or cross multiply to get the answer.

3 0
3 years ago
In the circle below, AD is a diameter and AB is tangent at A. suppose mADC=228. Find the measures of mCAB and mCAD. Type your nu
Tju [1.3M]

Answer:

m∠CAB = 66°

m∠CAD = 24°

Step-by-step explanation:

<em>m∠CAB</em>

The given parameters are;

The measure of arc m\widehat{ADC} = 228°

The diameter of the given circle = \overline{AD}

The tangent to the circle = \underset{AB}{\leftrightarrow}

The measure of m∠CAB and m∠CAD = Required

By the tangent and chord circle theorem, we have;

m∠CAB = (1/2) × m\widehat{AC}

However, we have;

m\widehat{AC} + m\widehat{ADC} = 360° the sum of angles at the center of a circle is 360°

∴ m\widehat{AC} = 360° - m\widehat{ADC}

Which gives;

m\widehat{AC} = 360° - 228° = 132°

m\widehat{AC} = 132°

Therefore;

m∠CAB = (1/2) × 132° = 66°

m∠CAB = 66°

<em>m∠CAD</em>

Given that  \overline{AD} is the diameter of the given circle, we have

The tangent, \underset{AB}{\leftrightarrow}, is perpendicular to the radius of the circle, and therefore \underset{AB}{\leftrightarrow} is also perpendicular to the diameter of the circle

∴ m∠DAB = 90° which is the measure of the angle formed by two perpendicular lines

By angle addition property, we have;

m∠DAB = m∠CAB + m∠CAD

∴ m∠CAD =  m∠DAB - m∠CAB

By substitution, we have;

m∠CAD = 90° - 66° = 24°

m∠CAD = 24°

7 0
2 years ago
Nancy has a bank account that has a balance of $320 and allows for a maximum of 6 deposits per month. She has decided that each
Dominik [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
The first term of an arithmetic progression is 4X and the second term is X^2. The common difference is 12. Find the possible val
katovenus [111]
4X,X^2,_
Common difference=12
second term - first term=12
X^2-4x=12
subtract 12 from both sides
X^2-4X-12=12-12
X^2-4X-12=0
now its a quadratic equation, so use either factor method or quadratic formula,
X^2-6X-2X-12=0
take common
x(X-6)-2(x-6)=0
x-2)(x-6)=0
so x is either 2 or 6 
now use them to find the third term
3 0
3 years ago
Read 2 more answers
Solve the problem.
Alex73 [517]
1234xxx0  1`= 21 x3 2= 21x 3 3 =21x3 4= 21x 3 5=21x3  6=21x3 7=21x3 8=21x3 9=21 x3  irt will take him 588 secs
5 0
3 years ago
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