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Keith_Richards [23]
3 years ago
7

A square piece of paper is folded in half vertically. The resulting figure has a perimeter of 21 in. What is the number of units

in the greatest possible perimeter?
Mathematics
1 answer:
Rudiy273 years ago
4 0

Perimeter is adding all 4 sides together.

To find the length and width divide total perimeter by 2:

21 / 2 = 10.5

We now know the length of 1 side and the width of 1 side need to equal 10.5.

Since the original piece was a square we also know the width needs to equal 1/2 of the length.


So we have L + 1/2L = 10.5

Add the common terms 1 L + 1/2 L = 1 and 1/2 L

To Find L divide 10.5 by 1-1/2, which equals 7

To find the width subtract 7 from 10.5, which equals 3.5

So the paper is now 3.5 inches by 7 inches.

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Answer: 
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>; 

Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
___________________________________
Explanation:

0.25 =  ¼ l  (less than "1"); the lowest of the three given values. 

The remaining two values have the same whole number of 3, and a fraction:
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The least common multiples among the denominators of the fraction values is 40.   ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40.  3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;  
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So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖; 
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