<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the population mean.
As per given , we have
Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given 
, so we perform one-tailed z-test.
Test statistic : 
, where = Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 , 
, , 
, we have
P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
If we are supposed to assume that QS=TV
4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4
sub back
4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV
then answer is C
Question
Tickets for a game Cost $2 for students and $5 for adults. The number of students was 3 less than 10 times the number of adults. The total amount of money from ticket sales was $619. How many of each tickets were sold?
Step-by-step explanation:
With g=3
Just replace every g with a 3.
So the equations becomes:
12g·(9÷g)=12(3)·(9÷(3))
This can also be written in the form:
Cancelling out the 3's:
12·9=108
