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Rus_ich [418]
3 years ago
8

In the early 19th century Christian Doppler, an Austrian physicist, proposed a theory regarding the properties of a moving sourc

e of sound. This is now known as Doppler’s law or the Doppler effect. What does this law state? A) The loudness of a moving source of sound is independent of the observer. B) The frequency of a moving source of sound is independent of the observer. C) The loudness of a moving source of sound is greater as it approaches an observer. D) The frequency of a moving source of sound is greater as it approaches an observer.
Physics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:  D) The frequency of a moving source of sound is greater as it approaches an observer.

Explanation:

Doppler effect occurs when there is relative motion between source of sound and observer. The apparent frequency observed by observed is different from the actual frequency of the sound emitted from the source.

When the source and observer move closer, the apparent frequency is greater and when moving away, it is less than the actual frequency. Thus, the correct option is D.

The loudness is dependent on the amplitude of the sound which remains same.

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Explanation:

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3 years ago
Why are the eggs and confectioner’s sugar amounts easy to work with to make 8 brownies?
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Answer:

Because they are both easy to measure (?)

Explanation:

(I'm not really sure, there are no choices. If there were different options I might be able to better answer this)

6 0
3 years ago
Would the solar panel work under a fluorescent or halogen light? explain your response being sure to relate your observations to
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4 0
3 years ago
In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.40×1016 kg and a ra
Arturiano [62]

A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

5 0
3 years ago
A car has a mass of 550 kg. What is the weight of the car?
lozanna [386]
1212.54 is what 550 kgs is equal to the weight of the car
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