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nika2105 [10]
4 years ago
8

27 g of Al will react with how much mass of O2 to produce Al2O3

Chemistry
1 answer:
snow_tiger [21]4 years ago
5 0
24g 4Al+3O2=2Al2O3
27g x(g)
108 96
X=24g
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What is the role of plastocyanin in the z-scheme model?
murzikaleks [220]

Answer:

It shuttles electrons between the cytochrome complex and photosystem I.

Explanation:

6 0
2 years ago
A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158
Zinaida [17]

Answer:

b. The final state of the substance is a gas.

d. The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Methane has the following properties:

  • Normal melting point: 90.7 K
  • Normal boiling point: 111.65 K

*"Normal" refers to normal pressure (1 atm).

According to this, we can affirm:

  • Below 90.7 K, methane is solid.
  • Between 90.7 K and 111.65 K, methane is liquid.
  • Above 111.65 K, methane is gas.

<em>A sample of methane at a pressure of 1.00 atm and a temperature of 93.1 K is heated at constant pressure to a temperature of 158 K. Which of the following are true? Choose all that apply.</em>

<em>a. The liquid initially present will solidify.</em>  FALSE. The liquid will vaporize.

<em>b. The final state of the substance is a gas.</em>  TRUE.

<em>c. The sample is initially a solid.</em>  FALSE. The sample is initially a liquid.

<em>d. The sample is initially a liquid. One or more phase changes will occur. </em>TRUE.

4 0
3 years ago
A self-contained underwater breathing apparatus (SCUBA) uses canisters containing potassium superoxide. The superoxide consumes
emmainna [20.7K]

Answer:

52.0004 grams of mass of potassium superoxide  is required

Explanation:

Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.

Pressure of the gas,P = 767 mm Hg = 0.9971 atm

Temperature of the gas,T = 22.0 °C = 295.15 K

Using an ideal gas equation to calculate the number of moles.

PV=nRT

n=\frac{0.9971 atm\times 8.90 L}{0.0821 atm L/mol K\times 295.15 K}

n = 0.3662 mol

4KO_2(s)+2CO_2(g)\rightarrow 2K_2CO_3(s)+3O_2(g)

According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.

Then 0.3662 mol of  of carbon-dioxide will react with:

\frac{4}{2}\times 0.3662 mol=0.7324 mol of potassium superoxide.

Mass of 0.7324 mol potassium superoxide:

0.7324 mol × 71 g/mol = 52.0004 g

52.0004 grams of mass of potassium superoxide is required.

8 0
3 years ago
How do I do number 64?
shutvik [7]
They are isotopes because isotopes have the same number of protons (atomic number) but can have different numbers of neutrons + protons (atomic mass).
5 0
3 years ago
If you start with 13 mole H2O and 50 grams of O2 what is the percent yield of H202 if 100 grams of H202 is actually made?
dmitriy555 [2]

Answer:

94.1 %

Explanation:

We firstly determine the equation:

2H₂O + O₂ →  2H₂O₂

2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.

We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol

Certainly oxygen is the limiting reactant.

2 moles of water react to 1 mol of oxygen.

13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)

As we determine the limiting reactant we continue to the products:

1 mol of O₂ can produce 2 moles of H₂O₂

Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles

We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g

That's the 100% yield or it can be called theoretical yield.

Percent yield = (Yield produced / Theoretical yield) . 100

(100g / 106.25 g) . 100 = 94.1 %

3 0
3 years ago
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