The initial sample has a molecular formula of MnSO₄·H₂O. This molecule is a hydrate as it has a unit of water within its structure for every molecule of MnSO₄. This sample is being dehydrated to remove the water to give.
MnSO₄·H₂O → MnSO₄ + H₂O
MnSO₄·H₂O has a molecular mass of 169.02 g/mol. While MnSO₄ has a molecular mass of 151 g/mol. Water has a molecular mass of 18.02 g/mol. We now can use the ratio of the mass of water to the mass of the initial sample to determine the percentage of each component by mass.
% water by mass:
18.02/169.02 x 100% = 10.7% Water by mass.
% MnO₄ by mass:
151/169.02 x 100% = 89.3% MnSO₄ by mass.
Water makes up 10.7% of the initial mass of MnSO₄·H₂O.
Answer:
c. Both i & ii
Explanation:
Moles do not change with temperature hence Mole fraction does not depends of temperature.
Molality is number of moles of solutes per kilogram of solvent. It has no relationship with temperature.
This means both of them do not change wit the change in temperature.
Correct option;
c. Both i & ii
Answer: <em><u>125 g</u></em>
Explanation:
Mass = Volume × Density
⇒ Mass of the water = 125 mL × 1.0 g/mL
= 125 g
