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Furkat [3]
4 years ago
11

When compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet,

a 3Hdoublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.

Chemistry
1 answer:
kati45 [8]4 years ago
4 0

Answer:

attached here is the diagram of the solution

Explanation:

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How does an increase in temperature affect the equilibrium concentration of the underlined substance and K for each of the follo
Darya [45]

Explanation:

Due to the positive value of the change in temperature, this is an endothermic reaction.

Since the forward reaction is endothermic, increasing the temperature increases the equilibrium constant (k).

In an equilibrium system, the position of the equilibrium will move in a way to annul the change made to the system. An increase in temperature for an endothermic reaction would favour the reaction, leading to increase in amount of products and decrease in amount of reactants.

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3 years ago
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Which way will the reaction shift if the volume is cut in half? a. toward the reactants b. toward the products c. the reaction w
erica [24]

The reaction will  shift toward the reactants if the volume is cut in half.

<h3 /><h3>Reactants </h3>

The initial components of a chemical reaction are called reactants. Chemical bonds between reactants are broken and new ones are created in order to create products. Reactants and products are listed on the left and right sides, respectively, of the arrow in a chemical equation.

Substances on both sides of an arrow that points left and right are both reactants and products in a chemical process (the reaction proceeds in both directions simultaneously). A chemical equation that is balanced has the same amount of atoms of each element in the reactants and products. Around 1900–1920 is when the word "reactant" was first used. There are instances when the word "reagent" is interchangeable.

Learn more about reactants here:

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5 0
2 years ago
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

Mass of methane CH4 (g) = 80.0 g.

Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

6 0
1 year ago
Write and label the density triangle
Slav-nsk [51]

Answer:

It is basically a way of telling you how to solve for different variables in the equation d=m/v

Explanation:

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3 years ago
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