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elena-14-01-66 [18.8K]
3 years ago
6

Buzz Aldrin is riding his lunar module "The Falcon" down to the moon’s surface. He is wearing his backpack, which weighs 1300 N

on Earth. During the descent, he is decelerating at a rate of 1.0 m/s2 . What is the apparent weight of his backpack during the descent? (It may be helpful to know that the acceleration due to gravity on the moon is 1/6th the value it is on Earth. Also,
Physics
1 answer:
LiRa [457]3 years ago
6 0

Answer:349.07 N

Explanation:

Given

Weight of Buzz =1300 N on earth

Thus mass m=\frac{1300}{9.8}=132.65 kg

it is given that it is decelerating at the rate of 1 m/s^2

Apparent weight is F_{net}

F_{net}=Mg_m-ma

here a =-1 m/s^2 as it is decelerating

F_{net}=132.56\times \frac{g}{6}+132.56\times 1

F_{net}=216.51+132.56=349.07 N

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Answer:

A simple pendulum with a period of 1 second will have a length of 0.25 meters or 25 centimeters

Explanation:

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7 0
3 years ago
A woman drives 6 miles, accelerating uniformly from rest to 70 mph. How long does it take for her to reach 70 mph?
Morgarella [4.7K]
Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0 

The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles

Vf = at
70 = at
a = 70/t---equation 1

d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2

Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
6= 35t
t= 0.17142 hours or 10.28571 mins or 617.14 sec



6 0
3 years ago
23. Lunar Gravity Compare the force holding a
romanna [79]

Explanation:

Given

mass of the rock is 10 kg

Force requires to hold the rock is equal to its weight

Weight is given by the product of mass and acceleration due to gravity

Weight on the earth surface

\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N

Weight on the moon surface

\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N

So, the force holding the rock on earth is approximately 6 times the force on the moon.

3 0
3 years ago
A throttle position sensor waveform is going to be observed. At what setting should the volts per division be set to see the ent
Mars2501 [29]

Answer:

1 V / div

Explanation:

Solution:

- The vertical scale has eight divisions.  

- If each division is set to equal 1 volt, the display will show 0 to 8 volts.  

- This is okay in a 0 to 5 volt variable sensor such as a throttle position (TP) sensor.  

- The volts per division (V/div) should be set so that the entire anticipated waveform can be viewed.

3 0
3 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
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