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VladimirAG [237]
3 years ago
14

When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40

ºc. if the heat capacity of the bomb calorimeter is 5.86 kj/°c, what is the change in internal energy of the combustion of biphenyl in kj?
Chemistry
1 answer:
slava [35]3 years ago
7 0
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

  =heat  capacity of  bomb  calorimeter x  delta  T  where  delta T   is  change   in temperature
delta T  = 29.4  -25.8= 3.6 c

= 5.86 kj/c   x  3.6 c =  21.096  kj


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Consider the following balanced equation. SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table, showing the appropriate numb
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Answer:

mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

      3                          9                          3                                6

      1                           3                           1                                2

     13                         39                         13                             26

    2.5                        7.5                       2.5                            5.0

    1.4                         4.2                        1.4                            2.8

Explanation:

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<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

  • It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.
  • We can complete the table of no. of moles of each component:

<u><em>1. 9.0 moles of C:</em></u>

We use the triple amount of C, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<u><em>2. 1.0 mole of SiO₂:</em></u>

We use the same amount of SiO₂ as in the balnced equation, so the no. of moles of other components will be the same as in the balanced equation.

So, it will be 1.0 moles of SiO₂ with 3.0 moles of C that produce 1.0 moles of SiC and 2.0 moles of CO.

<u><em>3. 26.0 moles of CO:</em></u>

We use the amount of CO higher by 13 times than that in the balanced equation, so we multiply the others by 13.0.

So, it will be 13.0 moles of SiO₂ with 39.0 moles of C that produce 13.0 moles of SiC and 26.0 moles of CO.

<u><em>4. 7.5 moles of C:</em></u>

We use the amount of C higher by 2.5 times than that in the balanced equation, so we multiply the others by 2.5.

So, it will be 2.5 moles of SiO₂ with 7.5 moles of C that produce 2.5 moles of SiC and 5.0 moles of CO.

<u><em>5. 1.4 moles of SiO₂:</em></u>

We use the amount of SiO₂ higher by 1.4 times than that in the balanced equation, so we multiply the others by 1.4.

So, it will be 1.4 moles of SiO₂ with 4.2 moles of C that produce 1.4 moles of SiC and 2.8 moles of CO.

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Oksana_A [137]

Answer:


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Generally Gas hydrates have two main applications. 

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