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VladimirAG [237]
3 years ago
14

When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40

ºc. if the heat capacity of the bomb calorimeter is 5.86 kj/°c, what is the change in internal energy of the combustion of biphenyl in kj?
Chemistry
1 answer:
slava [35]3 years ago
7 0
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

  =heat  capacity of  bomb  calorimeter x  delta  T  where  delta T   is  change   in temperature
delta T  = 29.4  -25.8= 3.6 c

= 5.86 kj/c   x  3.6 c =  21.096  kj


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. Through what three mechanisms do gamma rays interact with matter?
siniylev [52]

Answer:

Photoelectric effect, pair production and Compton scattering

Explanation:

Gamma rays, having no charge, can be slowed slowly by ionization as a material passes through. They suffer other mechanisms that eventually make them disappear, transferring their energy, they can cross several centimeters of a solid, or hundreds of meters of air, without undergoing any process or affecting the material they cross. Then they suffer one of the three effects and deposit much of their energy there. The three mechanisms of interaction with matter are: the photoelectric effect, the Compton effect and the production of pairs.

The photoelectric effect is that the photon meets an electron in the material and transfers all its energy, disappearing the original photon. The secondary electron acquires all the energy of the photon in the form of kinetic energy, and is sufficient to separate it from its atom and convert it into a projectile. This is stopped by ionization and excitation of the material

In the Compton effect the photon collides with an electron as if it were a clash between two elastic spheres. The secondary electron acquires only part of the energy of the photon and the rest takes it with another photon of lesser energy and diverted.

When an energy photon approaches the intense electric field of a nucleus, the production of pairs can happen. In this case the photon is transformed into an electron positron pair. Since the sum of the mass of the pair is 1.02 MeV, it cannot happen if the photon's energy is less than this amount. If the energy of the original photon is greater than 1.02 MeV, the surplus is distributed by the electron and the positron as kinetic energy, and the material can be ionized. The positron at the end of its path forms a positronium and then annihilates producing two annihilation photons, 0.51 MeV each.

3 0
3 years ago
10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters
kipiarov [429]

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of sodium carbonate = 10.6 g

Volume of water = 1.25 L

Molarity of solution = ?

Solution:

First of all we will calculate the moles of solute.

Number of moles = mass/molar mass

Number of moles = 10.6 g/ 106 g/mol

Number of moles = 0.1 mol

Formula:

Molarity = moles of solute / volume of solution in L

Now we will put the values in formula.

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

4 0
3 years ago
Match the following associations. Exothermic or endothermic
Alekssandra [29.7K]

<u>Answer:</u>

<em>1) ∆H is positive \Rightarrow Endothermic </em>

<em>2) E_p>E_r \Rightarrow Endothermic  </em>

<em>3) Energy is absorbed \Rightarrow Endothermic </em>

<em>4) E_r>E_p \Rightarrow Exothermic </em>

<em>5) ∆H is negtive \Rightarrow Exothermic </em>

<em></em>

<u>Explanation:</u>

∆H is called as enthalpy change  

It is also called as Heat of reaction

Energy is required for the bond to break a bond.

Energy is released when a bond is formed.

H_2+Cl_2>2HCl

that is

H-H+Cl-Cl>2H-Cl

We see in this equation, bonds between hydrogen and chlorine molecules gets broken and on the right side bond is formed in HCl.

If energy of products greater than energy of reactants then the reaction enthalpy change is endothermic .

If energy of products lesser than energy of reactants then the reaction enthalpy change is exothermic .

For example  

\Delta H=E_p-E_r

=30KJ-20KJ

=+10KJ

(positive hence endothermic)

\Delta H=E_p-E_r

=10KJ-40KJ

=-30KJ

(negative hence exothermic)

8 0
4 years ago
A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume
jenyasd209 [6]
Volume of Argon V1 = 5.0 L  
Pressure of Argon P1 = 2 atm 
Final temperature T2 = 30 C = 30 + 273 = 303 K 
Volume at final temperature V2= 6 L 
Pressure at final temperature P2 = 8 atm  
We know that (P1 x V1) / T1 = (P2 x V2) / T2  
(2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48 
Initial Temperature T1 = 3030 / 48 = 63.12 
Initial Temperature = -209. 8 C
4 0
3 years ago
Which answer is INCORRECT not the correct one ​
Elena L [17]

Explanation:

It's 4

Hope it's help....

<h3>^_^</h3>
6 0
3 years ago
Read 2 more answers
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