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jolli1 [7]
2 years ago
10

At 580 k, 6. 42% of the molecules are in the chair form. calculate the value of the equilibrium constant for the reaction as wri

tten above.
Chemistry
1 answer:
Ann [662]2 years ago
5 0
Equilibrium chemical reaction between chair and boat forms is:
Kc = \frac{[Boat form]}{[Chair form]}
Suppose the total number of molecules is x 
Number of molecules of chair form is 6.42/100 x
Number of molecules of boat form is 93.58/100 x
Kc = \frac{(0.9358x)}{(0.0642x)} = 14.6
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3 years ago
What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm
gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

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In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

a^{2} + a^{2} = (4R)^{2}     (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm      

By solving equation (1) for "a" we have:

a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm    

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.   

I hope it helps you!

7 0
3 years ago
How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?
shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = 4.18J/g^oC

T_1 = initial temperature  = 25.0^oC

T_2 = final temperature  = 37.0^oC

Now put all the given value in the above formula, we get:

Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K

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3 0
2 years ago
What is the balanced form of the chemical equation shown below?
oksian1 [2.3K]

Answer:

c

Explanation:

it is the right answer

4 0
3 years ago
How many molecules are in 3.5 moles of ethanol
nasty-shy [4]
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1 mole of Ethanol molecule contains 6.02 * 10²³ molecules


3.5 moles of Ethanol will then contain:        3.5 * 6.02 * 10²³

                                                                       = 2.107 * 10²⁴ molecules.
5 0
3 years ago
Read 2 more answers
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