2 years ago

Dada la recta 3x +4y - 12=0 encontrar los puntos de interseccion de la parábola y^2=-9x

Mathematics

1 answer:

Radda [10]2 years ago

3 0

Answer:

(-4 , 6)

Step-by-step explanation:

3x +4y - 12=0

x = 1/3 × (12-4y)

y² = 9 × 1/3 × (12-4y) = 36 -12y

y² + 12y -36 =0

(y -6)² = 0

y = 6

x = -4

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Dada la recta 3x +4y - 12=0 encontrar los puntos de interseccion de la parábola y^2=-9x​

Dada la recta 3x +4y - 12=0 encontrar los puntos de interseccion de la parábola y^2=-9x