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Readme [11.4K]
3 years ago
14

A solution is made by dissolving 373.5 g of Pb(NO3)2 (molar mass: 331.2 g/mol) in 2.00 × 103 g of water. What is the molality of

the solution?
Chemistry
2 answers:
hram777 [196]3 years ago
7 0
Answer:
molality = 0.564 m

Explanation:
Molality =  number of moles of solute / kg of solvent

1- getting moles of solute:
number of moles = mass / molar mass
we have:
mass = 373.5 g
molar mass = 331.2 g/mol
Therefore:
number of moles = 373.5 / 331.2 = 1.128 moles

2- getting kg of solvent:
mass in kg = mass in grams * 10⁻³
mass in kg = 2 * 10³ * 10⁻³
mass in kg = 2 kg

3- getting molality:
Molality =  number of moles of solute / kg of solvent
Molality = 1.128 / 2
Molalty = 0.564 m

Hope this helps :)
julsineya [31]3 years ago
5 0

Answer:

0.564

Explanation:

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Does this equation obey the law of conservation of mass: 2Z + 2HCI ➡️ ZnCI2 + H2​
MAXImum [283]

Answer:

2Zn + 2HCI ➡️ ZnCI2 + H2​

LHS of equation

Z = 2

H = 2

Cl = 2

RHS of equation

Zn = 1

Cl =2

H =2

as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass

Explanation:

the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.

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3 years ago
What is the mass of an object that has a density of 0.500 g/cm3 and a volume of 5.00 mL?
attashe74 [19]

Answer:

<h2>The answer is 2.5 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.5 g/cm³

1 mL = 1 cm³

5 mL = 5 cm³

volume = 5 cm³

The mass is

mass = 0.5 × 5

We have the final answer as

<h3>2.5 g</h3>

Hope this helps you

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3 years ago
Is water wet? I give you a lot of points
UkoKoshka [18]

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Answer:

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Explanation:

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2 years ago
A 65.0-gram sample of some unknown metal at 100.0° C is added to 100.8 grams of water at 22.0° C. The temperature of the water r
vampirchik [111]
We do a heat balance to solve this:
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The specific heat of the metal is 0.44 J/ (°C × g)
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3 years ago
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