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qaws [65]
3 years ago
12

A compound contains 72% magnesium and 28% nitrogen. What is its empirical formula?

Chemistry
1 answer:
SashulF [63]3 years ago
7 0

So the empirical formula is Mg3N2

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In the game of economics, goods are objects that fulfill peoples needs and ____.
Evgen [1.6K]

Goods are objects that fulfill peoples needs and wants.


4 0
3 years ago
We say that salts will dissociate but acids will react with water. We say that acids will
Paha777 [63]

Answer:

ionize

Explanation:

Acids are chemical substances that lose/donate their hydrogen ion (H+) when they react with water. This property of acids is termed IONIZATION. In a chemical reaction involving acids and bases, acids release their proton or hydrogen ion (H+) in the presence of water solutions to form a conjugate base, which is usually an anion.

For example, in the chemical reaction;

HX + H20 -------> X- + H30+

HX is the acid because it loses its electron to water and forms the anion, X-, which is the conjugate base. Hence, it can be said that acid HX ionizes in water.

7 0
3 years ago
Can anyone here help me with chemistry
Kay [80]
The answer is 20g N2
5 0
2 years ago
The periodic table is based on an element's
grin007 [14]
Well, TECHNICALLY, the periodic table is "based" upon a whole myriad of characteristics. But if you're talking about the consecutive arrangement of elements...it would be B, the atomic number.
3 0
3 years ago
What is the final concentration of cl- ion when 250 ml of 0.20 m cacl2 solution is mixed with 250 ml of 0.40 m kcl solution? (as
serious [3.7K]

CaCl2 and KCl are both salts which dissociate in water when dissolved. Assuming that the dissolution of the two salts are 100 percent, the half reactions are:

<span>CaCl2 ---> Ca2+  +  2 Cl-</span>

KCl ---> K+ + Cl-

Therefore the total Cl- ion concentration would be coming from both salts. First, we calculate the Cl- from each salt by using stoichiometric ratio:

Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles Cl / 1 mole CaCl2)

Cl- from CaCl2 = 0.1 moles

 

Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1 mole KCl)

Cl- from KCl = 0.1 moles

 

Therefore the final concentration of Cl- in the solution mixture is:

Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)

Cl- = 0.2 moles / 0.5 moles

<span>Cl- = 0.4 moles             (ANSWER)</span>

6 0
3 years ago
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