Volumen = constant => P/T = constant
T1 = 21°C + 273.15 = 294.15 k
P1 = 0.82 atm
T2 = - 3.5°C + 273.15 = 269.65 k
P2 = ?
P2 / 269.65k = 0.82atm / 294.15k
P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm
A 1 F solution stands 1 formula unit per litre and 0.01 F describes the concentration of solution with no deliberation for the real form of existence of species.
Molarity is defined as the ratio of moles of solute to the volume of solution in litres and it is used to describe formality. For accuracy, it is essential to expressed molarity of each species. In case of acetic acid, the molarity of acetic acid molecules is less than 0.01 M due to dissociation.
Thus, it is more precise to say that the concentration of a solution of acetic acid is 0.01 F instead of 0.01 M.
Answer:
280.8 g
Explanation:
Definimos la reaccion:
2NaOH + FeSO₄ → Na₂SO₄ + Fe(OH)₂
Como tenemos la masa de NaOH, asumimos que el sulfato de hierro (II) es el reactivo en exceso.
Definimos masa de reactivo: 250 g . 1mol / 40g = 6.25 mol
2 moles de NaOH producen 1 mol de hidroxido ferroso
Entonces 6.25 moles producirán, la mitad (6.25 . 1) /2 = 3.125 moles
Convertimos los moles a masa:
3.125 mol . 89.85 g/mol = 280.8 g
Answer:
C) It moves faster and collects more data
Explanation:
