Question

(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 10g Na + 10g Oxygen.

Answer 1

13.5g

Explanation:

Given parameters:

Mass of Na = 10g

Mass of O₂ = 10g

Unknown:

Mass of products formed = ?

Balanced equation = ?

Solution:

The balanced chemical equation is shown below:

                  4Na       +     O₂     ⇒      2Na₂O

In any reaction, the specie in short supply determines the extent of the reaction.

This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.

  let us convert to moles;

    Number of moles of Na = $\frac{mass }{molar mass} = \frac{10}{23}$ = 0.435mole

 Number of moles of O₂ = $\frac{mass}{molar mass} = \frac{10}{32}$ = 0.313mole

From the given equation;

   4 moles of Na requires 1 mole of O₂;

  0.435 moles of Na will require $\frac{0.435}{4}$ = 0.11 moles

 But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles

We see that Na is the limiting reagent;

   4 moles of Na gives 2 mole of Na₂O

   0.435 moles of Na will give $\frac{0.435 x 2 }{4}$ = 0.22 moles

Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g

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Number of moles brainly.com/question/1841136

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