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Sunny_sXe [5.5K]
3 years ago
14

Household bleach which has a ph of 12.6 has more hydroxide (oh-) ions than lye which has a ph of 13.

Chemistry
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

Household bleach has more hydroxide ions than lye.

Explanation:

The pH of the solution id the negative logarithm of hydrogen ion concentration in an aqueous solution.

pH=-\log[H^+]

  • Higher the pH value lessor the hydrogen ion concentration in the solution. Higher will be the concentration of hydroxide ions
  • Lower the pH value higher the hydrogen ion concentration in the solution.Lower will be the concentration of hydroxide ions.

The pH of the household bleach = 12.6

12.6=-\log[H^+]

[H^+]=2.511\times 10^{-13} M

The pH of the lye= 13

13=-\log[H^+]

[H^+]= 10^{-13} M

Since , house hold bleach has the lower pH than lye which means that it will have higher concentration of hydroxide ions.

Arisa [49]3 years ago
6 0

Answer is: false, concentration of hydroxide ions is greater in lye than in household bleach.

1) pH = 12.6.

pH + pOH = 14.

pOH = 14 - 12.6.

pOH = 1.4.

pOH = -log[OH⁻] ⇒ [OH⁻] = 10∧(-pOH).

[OH⁻] = 10∧(-1.4) = 0.039 M; concentration of hydroxide ions.

2) pH = 13.

pOH = 14 - 13.

pOH = 1.

[OH⁻] = 10⁻¹ M = 0.1 M.

0.1 M > 0.039 M.

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Butoxors [25]

Answer:

The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution

Explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

Therefore, the concentration of the required solution = 0.250 moles/liter

The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters

The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

Therefore the number of liters required to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

8 0
3 years ago
UHHH helpppp maya cause uh she d.a.n.g d.u.m.b.
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Answer:

17

Explanation:

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6 0
3 years ago
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Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

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Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

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5 0
3 years ago
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denpristay [2]

Another product: CO₂

<h3>Further explanation</h3>

Given

Reaction

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Required

product compound

Solution

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if we look at the reaction above, there are C atoms on the left (reactants), so that in the product there will also be C atoms with the same number of C atoms on the left

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