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Sunny_sXe [5.5K]
3 years ago
14

Household bleach which has a ph of 12.6 has more hydroxide (oh-) ions than lye which has a ph of 13.

Chemistry
2 answers:
Elena-2011 [213]3 years ago
7 0

Answer:

Household bleach has more hydroxide ions than lye.

Explanation:

The pH of the solution id the negative logarithm of hydrogen ion concentration in an aqueous solution.

pH=-\log[H^+]

  • Higher the pH value lessor the hydrogen ion concentration in the solution. Higher will be the concentration of hydroxide ions
  • Lower the pH value higher the hydrogen ion concentration in the solution.Lower will be the concentration of hydroxide ions.

The pH of the household bleach = 12.6

12.6=-\log[H^+]

[H^+]=2.511\times 10^{-13} M

The pH of the lye= 13

13=-\log[H^+]

[H^+]= 10^{-13} M

Since , house hold bleach has the lower pH than lye which means that it will have higher concentration of hydroxide ions.

Arisa [49]3 years ago
6 0

Answer is: false, concentration of hydroxide ions is greater in lye than in household bleach.

1) pH = 12.6.

pH + pOH = 14.

pOH = 14 - 12.6.

pOH = 1.4.

pOH = -log[OH⁻] ⇒ [OH⁻] = 10∧(-pOH).

[OH⁻] = 10∧(-1.4) = 0.039 M; concentration of hydroxide ions.

2) pH = 13.

pOH = 14 - 13.

pOH = 1.

[OH⁻] = 10⁻¹ M = 0.1 M.

0.1 M > 0.039 M.

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why do you think Kool Aid comes in packets that has a very finely ground powder (finely ground means very small particles).
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Answer:

Answer 1:

When you pour the kool-aid into water, the little crystals go straight to the bottom because they are heavier than the water. If you left them there without stirring, and came back a few days later, you wouldn't see any crystals on the bottom. That's because the stuff in kool-aid can DISSOLVE in water, which means that each little molecule of kool-aid gets suspended between the molecules of water. When that happens, you can't see the kool-aid anymore...it's trapped between the water molecules. When you stir kool-aid, you help DISSOLVE the kool-aid in water by keeping all of the crystals off the bottom and in the water. So you see, stirring kool-aid speeds up the dissolving,

Answer 2:

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Answer 3:

I'm not a chemist, but I think I can answer your question about Kool-Aid. Kool-Aid is mostly sugar, which is heavier than water, so when you pour it in it sinks to the bottom. When you stir it up the sugar (and flavoring) dissolves so that you don't have any solid particles any more. Stuff that is dissolved in water will not sink because it is no longer a physically separate thing. It becomes part of the water (or water-sugar-flavor solution). What happens if you pour the Kool-Aid in but don't stir it? Will it eventually dissolve? You may have to wait a long time, like over night. Try it and let me know what you find!

Answer 4:

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Now I have an experiment for you. What happens if you mix up some Jello and instead of letting it sit still, you keep stirring it??? WILL THE JELLO EVER SET??

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8 0
3 years ago
How many hydrogen atoms are attached to each carbon adjacent to a double bond? nurition?
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That depends. there are 2 possible answers.
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The Carbon on the right of the double bond has 2
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I'm not sure what you should put. It's one of those things that I would repeat my argument and submit it.
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4 years ago
A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom
Taya2010 [7]

Answer:

28/95 = 29.,5 % of Arsine decomposed

Explanation:A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?

Answer in units of %.

initial pressure 332 Torr initial volume 0.46 L initial temperature 223K

final pressure 488 Torr final volume 0.46 L final 273 K

Torr is 1/760 atm 332 torr = 0.437 atm 488 Torr =0.642 atm

PV = nRT so n=RT/PV

INITIAL n= 0.082 X 223/(0.437)(0.46) = 91 moles

final n= 0.082 X 273 / (.437)(488) = 105 moles

2AsH3----------> 2As + 3H2

x moles of Arsine decomposed to make 1.5 moles of H2

the final number of moles was

(91 -X)+ 1.5 X = 105 moles

91 + 0.5 X = 105

0.5 X = 14

X =28

CHECK

if 28 moles of Arsine , then the container would have

91 --28 + 1.5(28) = 91 +14 =105 check

so 28/95 = 29.,5 % of Arsine decomposed

Your answer

(quit)

polyalchemVirtuoso

Answer:

Explanation:

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