Question

What is the path of an electron moving at 4 000 m/s perpendicular to a magnetic field of 1.5 T? (me = 9.11 x 10^-31kg)

Answer 1

Answer:

$15.18\times 10^{-9} m$

Explanation:

Radius of the path of electron which is moving perpendicular to magnetic field is defined as,

$r=\frac{mv}{qB}$

Here, m is the mass of electron, v is the velocity of electron, q is the charge on electron, and B is the magnetic field.

Given that, the velocity of electron is, $v=4000m/s$.

And the magnetic field is $B=1.5T$.

And the mass of electron is, $m=9.11\times10^{-31}kg$

And the charge on electron is, $q=1.6\times 10^{-19}C$

Put all these values in radius equation,

$r=\frac{9.11\times10^{-31}kg\times 4000m/s }{1.6\times 10^{-19}C\times 1.5T}\\r=15.18\times 10^{-9} m$

Therefore, the path radius of a moving electron is $15.18\times 10^{-9} m$