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balu736 [363]
3 years ago
13

Does the nuclear mass or the charge of the nucleus determine what element an atom is?

Physics
2 answers:
riadik2000 [5.3K]3 years ago
6 0

Answer:

All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons. which have a positive electrical charge, and neutrons, which have no charge. All atoms have at least one proton in their core, and the number of proton determines which kind of element an atom is

Explanation:

GarryVolchara [31]3 years ago
6 0

Neither the mass alone nor the charge alone tells you what element the atom's nucleus is.

The only charged particles in the nucleus are the protons, which are positively charged.  So every atom has a positively charged nucleus. The <em>NUMBER of protons in the nucleus</em> is the unique thing about each element.

It's not the mass, because there are also neutrons in the nucleus. A neutron has the same mass as a proton has, but no charge. AND, just to make it a little more complicated, every element can have atoms with a few <u><em>different</em></u> numbers of neutrons in the nucleus, so atoms of that element can have a few different masses. (These are called "isotopes" of that element.)

Bottom line:

-- The element is identified by the number of protons in the nucleus.

-- The nuclear charge is positive (that number), and

-- The nuclear mass is (that number) + (the number of neutrons in it).

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Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.
pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is  D = 0.59 \  m    

Explanation:

From the question we are told that

      The best resolution is  \theta  =  0.3 \  arcsecond

       The  wavelength is  \lambda  =  700 \  nm =  700 *10^{-9 } \  m

       

Generally the

         1 arcminute  = >  60 arcseconds

=>      x arcminute =>   0.3 arcsecond

So

       x =  \frac{0.3}{60 }

=>    x = 0.005 \  arcminutes

Now

         60 arcminutes  =>  1 degree

          0.005 arcminutes = >  z degrees  

=>       z =  \frac{0.005}{60 }

=>      z =  8.333 *10^{-5}  \ degree

Converting to radian  

           \theta  = z =  8.333 *10^{-5}  * 0.01745 = 1.454 *10^{-6} \  radian

Generally the resolution is mathematically represented as

            \theta  =  \frac{1.22 *  \lambda  }{ D}

=>    D =  \frac{1.22 * \lambda }{\theta }

=>     D =  \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }    

=>     D = 0.59 \  m    

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2 years ago
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