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den301095 [7]
4 years ago
13

A ray of light traveling in air is incident on the flat surface of a piece of glass at an angle of 65.9° with respect to the nor

mal to the surface of the glass. If the ray refracted into the glass makes an angle of 34.8° with respect to the normal, what is the refractive index of the glass?
Physics
1 answer:
stich3 [128]4 years ago
6 0

Answer:

n_{glass} = 1.6

Explanation:

\theta _{i} = Angle of incidence = 65.9°

\theta _{r} = Angle of refraction = 34.8°

n_{air} = Index of refraction of air = 1

n_{glass} = Index of refraction of glass = ?

Using Snell's law

n_{air} Sin\theta _{i} = n_{glass} \theta _{r}

(1) Sin65.9 =  n_{glass} Sin34.8

n_{glass} = 1.6

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Which movement causes day and night on Earth?
Brilliant_brown [7]

Answer:

The rotation of Earth

5 0
3 years ago
Read 2 more answers
There are 92 naturally occurring elements. How does this relate to the number of compounds?
raketka [301]

C) Elements combine in different ways to create many more than 92 compounds.

Explanation:

The number of elements we have relates to the compound formation in that, elements combine in different ways to create many more than 92.

Elements are distinct substances that cannot be split up into simpler substances. Such substances are only made up of one kind of atom.

Compounds are substances that are made up of two or more kinds of atoms joined together in a definite grouping.

  • Several millions of compounds are known because elements can combine in different ways.
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Learn more:

Chemical reactions brainly.com/question/3953793

#learnwithBrainly

3 0
4 years ago
A square loop of length 0.1 m on each side is sitting in a magnetic field that is increasing at a rate of 0.1 T/second. What can
Zolol [24]

Answer:

The induced emf can be found by Faraday’s Law.

\epsilon = -\frac{d\Phi_B}{dt}

\Phi_B = BA = B(0.1)^2 = 0.01B

The magnetic field is increasing at a rate of 0.1T/s. So,

\frac{dB}{dt} = 0.1

Finally,

\epsilon = \frac{dBA}{dt} = 0.01\frac{dB}{dt} = 0.01\times 0.1 = 0.001 V

Explanation:

Faraday’s Law states that a change in the magnetic flux induces an emf in the circuit. The magnetic flux is the multiplication of magnetic field and the area of the loop. The area of the loop is simple, and the change of magnetic field as a function of time is given in the question.

The minus sign in front of the Faraday’s Law means that the induced current always opposes the change of the magnetic flux. Since we do not know the direction of the magnetic field in this question, we cannot find the direction of the induced emf on the loop.

4 0
3 years ago
Assume that when you stretch your torso vertically as much as you can, your center of mass is 1.0 m above the floor. The maximum
Elenna [48]

1) 0.77 m

2) 0.23 m

Explanation:

1)

Here we want to find the time elapsed for crouching in order to jump and reach a height of 2.0 m above the floor, starting from 1.0 m above the floor.

First of all, we start by calculating the speed required to jump up to a height of 2.0 m. Since the total energy is conserved, the initial kinetic energy is converted into gravitational potential energy, so:

\frac{1}{2}mv^2 = mgh

where

m is the mass of the man

v is the speed after jumping

g=9.8 m/s^2 is the acceleration due to gravity

h = 2.0 - 1.0 = 1.0 m is the change in height

Solving for v,

v=\sqrt{2gh}=\sqrt{2(9.8)(1.0)}=4.43 m/s

In the acceleration phase, we know that the initial velocity is

u=0

And the force exerted on the floor is 2.3 times the gravitational force, so

F=2.3 mg

This means the net force on you is

F_{net} = F-mg=2.3mg-mg=1.3 mg

because we have to consider the force of gravity acting downward.

So the acceleration of the man is

a=\frac{F_{net}}{m}=\frac{1.3mg}{m}=1.3g

Now we can use the  following suvat equation to find the displacement in the acceleration phase, which is how low the man has to crouch in order to jump:

v^2-u^2=2as

where s is the quantity we want to find. Solving for s,

s=\frac{v^2-u^2}{2a}=\frac{4.43^2-0}{2(1.3g)}=0.77 m

2)

At the beginning, we are told that the height of the center of mass above the floor is

h = 1.0 m

During the acceleration phase and the crouch, the height of the center of mass of the body decreases by

\Delta h = -0.77 m

This means that the lowest point reached by the center of mass above the floor during the crouch is

h'=h+\Delta h = 1.0 - 0.77 = 0.23 m

This value seems unpractical, since it is not really easy to crouch until having the center of mass 0.23 m above the ground.

3 0
3 years ago
Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude, the rest position, and
Minchanka [31]

Answer:

Please find attached, the required wave drawn with MS Excel

Explanation:

Functions that represent waves is given as follows

A general form of the wave equation is A·sin(B·x) + D

Where;

B = 2·π/T

T = The period of the wave = 1/f

D = The vertical shift of the wave = 0

A = The amplitude of the wave = 1 for sine wave

v = The wave velocity

λ = The wavelength of the wave

f = The frequency of the wave

v = f·λ

At constant <em>v</em>, λ ∝ 1/f  

∴ λ ∝ T

Where T = 3, we have;

B = 2·π/T

∴ B = 2·π/3

Therefore, we have the wave with an amplitude of 1 cm, and wavelength, 3 cm, given as follows

y = sin((2·π/3)·x)

Plotting the above wave with MS Excel, we can get the attached wave

4 0
3 years ago
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