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insens350 [35]
3 years ago
7

Two forces, a 60.-newton force east and an 80.-newton force north, act concurrently on an

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
<span>1.0 cm = 10. N ± 1 N.</span>
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Two different sources of radiation give the same dose equivalent in Sv. Does this mean that the radiation from each source has t
Alisiya [41]

The product of the dosage Gy and relative biological efficiency yields a radiation dose equivalent Sv (RBE).

Sv =dose in Gy * RBE Sv=dose in GyRBE

The quantity of ionising energy absorbed by 1 text kg1 kg of tissue is defined as a radiation dose Gy. While RBE is a measure of a specific dose's biological effect relative to the biological effect of an equal quantity of X rays.

<h3>What is radiation?</h3>

Radiation is energy that moves through space at the speed of light from a source. This energy is coupled with an electric and magnetic field, and it exhibits wave-like qualities. Radiation is sometimes known as "electromagnetic waves."

Nature has a diverse variety of electromagnetic radiation. One example is visible light.

X-rays and gamma rays are extremely energetic. They may take electrons from atoms when they engage with them, causing the atom to become ionised.

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5 0
2 years ago
What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly incr
mariarad [96]

Answer:

the balls would move closer to each other

Explanation:

8 0
2 years ago
Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is l =  1.0 \ km  =  1000 \  m

       The speed of  A is  v__{A}} =  20 \ m/s

       The uniform acceleration of  B is  a__{B}} =  0.333 \ m/s^2

  Generally the time taken by go-cart  A is mathematically represented as

              t__{A}} = \frac{l}{v__{A}}}

=>          t__{A}} = \frac{1000}{20}

=>           t__{A}} =  50 \  s

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             l =  ut__{B}} + \frac{1}{2}  a__{B}} * t__{B}}^2

given that go-cart B starts from rest  u =  0 m/s

So

            1000 =  0 *t__{B}} + \frac{1}{2}  * 0.333  * t__{B}}^2

=>         1000 =  0 *t__{B}} + \frac{1}{2}  0.333  * t__{B}}^2            

=>         t__{B}} =  77.5 \  seconds  

 

Comparing  t__{A}} \  and  \ t__{B}}  we see that t__{A}} is smaller so go-cart A is  faster

   

       

3 0
2 years ago
Ten students stand in a circle and are told to make a transverse wave. What best describes the motion of the students? Each stud
Bond [772]

Lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students. Option D is correct.

<h3>What is a Transverse wave?</h3>
  • The wave in which the oscillation of particles is is perpendicular to the direction of energy transfer.

  • The students can make a transverse wave by raising their hands up and then down, one student at a time.

  • The raised hand represents the oscillation of particles while the sequence of the raising hand represents the direction of energy transfer.

Therefore, lifting hands and the down by one student at a time best describe the presentation of the transverse wave by students.

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3 0
2 years ago
Read 2 more answers
A merry-go-round is spinning at a rate of 4.04.0 revolutions per minute. Cora is sitting 0.50.5 m from the center of the merry-g
dsp73

Answer:

angular speed of both the children will be same

Explanation:

Rate of revolution of the merry go round is given as

f = 4.04 rev/min

so here we have

f = \frac{4.04}{60} =0.067 rev/s

here we know that angular frequency is given as

\omega = 2\pi f

\omega = 2\pi(0.067)

\omega = 0.42 rad/s

now this is the angular speed of the disc and this speed will remain same for all points lying on the disc

Angular speed do not depends on the distance from the center but it will be same for all positions of the disc

7 0
3 years ago
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