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insens350 [35]
3 years ago
7

Two forces, a 60.-newton force east and an 80.-newton force north, act concurrently on an

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
<span>1.0 cm = 10. N ± 1 N.</span>
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A loop of wire lays flat on a horizontal surface in an area with uniform magnetic field directed vertically down. Magnetic field
zimovet [89]

Answer:

B. counterclockwise

Explanation:

We shall apply Lenz's law to find direction of induced current . According to it , direction of induced current is such that the magnetic field produced  by it will try to nullify the change in  magnetic field that produces it. Increase in magnetic field in down ward direction is producing it so to nullify it , magnetic field induced will be in upward direction.  For it current induced will be anticlockwise.

4 0
3 years ago
The missile s engine exerts a 260-kN force F.
alexdok [17]

Answer:

a)F=(208 i+156 j) kN

b)F+W=219 kN

Explanation:

Solution:

To determine the components of F

F=(260 kN).(\frac{4}{\sqrt{4^{2}+3^{2}}}i+\frac{3}{\sqrt{4^{2}+3^{2}}}j)

 =(208 i+156 j) kN

F=(208 i+156 j) kN

b)weight W expressed in component and add into the    

   Force F.

W=-(8800 kg).(9.81 m/s^2)j

F+W=(208 i+[156-86.3]j) kN

F+W=\sqrt{(208kN)^{2}+(-69.7kN)^{2}  }

         =219 kN

F+W=219 kN

6 0
3 years ago
1. Why are some countries so poor while others are so rich?
irina [24]

Answer:

It depends on how much resources a country has.

8 0
2 years ago
A rock is thrown upwards and has a max altitude of 40 m. What was its initial velocity?
Natali [406]

Recall the formula,

{v_f}^2-{v_i}^2=2a\Delta x

where v_i and v_f are the rock's initial and final velocities, respectively; a is its acceleration; and \Delta x is the displacement it undergoes.

At any point during its motion, the rock is subject to gravity, so a=-g, where g=9.80\frac{\rm m}{\mathrm s^2}. At its maximum height, the rock has zero vertical velocity, and if we take its starting height to be the origin, we have \Delta x=x_{\rm max}.

So,

0^2-{v_i}^2=-2gx_{\rm max}\implies-{v_i}^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(40\,\mathrm m\implies\boxed{v_i=28\dfrac{\rm m}{\rm s}}

5 0
3 years ago
A nonuniform, 80.0-g, meterstick balances when the support is placed at the 51.0-cm mark. At what location on the meterstick sho
Gnoma [55]

Answer:34 cm

Explanation:

Given

mass of meter stick m=80 gm

stick is balanced when support is placed at 51 cm mark

Let us take 5 gm tack is placed at x cm on meter stick so that balancing occurs at x=50 cm mark

balancing torque

80\times 10^{-3}(51-50)=5\times 10^{-3}(50-x)

80=5(50-x)

80=250-5x

5x=170

x=\frac{170}{5}

x=34 cm

4 0
3 years ago
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