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insens350 [35]
3 years ago
7

Two forces, a 60.-newton force east and an 80.-newton force north, act concurrently on an

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
<span>1.0 cm = 10. N ± 1 N.</span>
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A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball's acceleration?
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Answer:

-2.5m/s²

Explanation:

The acceleration of a body is giving by the rate of change of the body's velocity. It is given by

a = Δv / t        ----------------(i)

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a = acceleration (measured in m/s²)

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t = time taken for the change (measured in seconds(s))

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i. initial velocity = 5m/s

final velocity = 0 [since the body (ball) comes to rest]

Δv = 0 - 5 = -5m/s

ii. time taken = t = 2s

<em>Substitute these values into equation (i) as follows;</em>

a = (-5m/s) / (2s)

a = -2.5m/s²

Therefore, the acceleration of the ball is -2.5m/s²

NB: The negative sign shows that the ball was actually decelerating.

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