Two forces, a 60.-newton force east and an 80.-newton force north, act concurrently on an
1 answer:
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Answer:
0.02 m
Explanation:
R₁ = initial distance jumped by jumper = 7.4 m
R₂ = final distance jumped by jumper = ?
θ₁ = initial angle of jump = 45°
θ₂ = final angle of jump = 42.9°
= speed at which jumper jumps at all time
initial distance jumped is given as
final distance jumped is given as
Dividing final distance by initial distance
distance lost is given as
d =
d = 7.4 - 7.38
d = 0.02 m
ANSWER:
250 J
STEP-BY-STEP EXPLANATION:
F = 20N is required to stretch the spring by 4 meters
We know that the force is equal to:
We solve for k (spring constant):
The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:
The work required is 250 joules.