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3 years ago

What scientific laws did Newton present in Principia?

Chemistry

2 answers:

Simora [160]3 years ago

8 0

................... Google is the way

Rama09 [41]3 years ago

7 0

Answer:

The Principia states Newton's laws of motion, forming the foundation of classical mechanics; Newton's law of universal gravitation; and a derivation of Kepler's laws of planetary motion (which Kepler first obtained empirically). The Principia is considered one of the most important works in the history of science.

Explanation:

Uhhhhh I googled it but If I am correct I believe that the laws of motion are Every object moves in a straight line unless acted upon by a force. 2. The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass. 3. For every action, there is an equal and opposite reaction.

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The side chains of amino acids may contain..

salantis [7]

The correct answer is d)all of above

examples for a are tyrosine for b lysine and for c isoleucine

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3 years ago

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The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equati

valkas [14]

Answer:

(a) $p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) $Dissociation =0.99$

Explanation:

Hello,

(a) In this case, for the given chemical reaction, the law of mass action becomes:

$Kc=\frac{[C6H5CHO][H2]}{[C6H5CH2OH]}$

In such a way, as 1.20 g of benzyl alcohol are placed into a 2.00-L vessel, the initial concentration is:

$[C6H5CH2OH]_0=\frac{1.20g*\frac{1mol}{108.14g} }{2.00L} =5.55x10^{-3}M$

Hence, by writing the law of mass action in terms of the change $x$ due to equilibrium:

$Kc=\frac{(x)(x)}{5.55x10^{-3}-x}=0.558$

Solving for $x$ by using a quadratic equation one obtains:

$x=5.50x10^{-3}M$

Thus, the equilibrium concentration of benzyl alcohol is computed:

$[C6H5CH2OH]_{eq}=5.55x10^{-3}M-5.50x10^{-3}M=5x10^{-5}M$

With that concentration the partial pressure results:

$p_{C6H5CH2OH}=[C6H5CH2OH]_{eq}RT =5x10^{-5}\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*523K \\p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) Now, the fraction of benzyl alcohol that is dissociated relates its equilibrium concentration with its initial concentration:

$Dissociation=\frac{C6H5CH2OH_{eq}}{C6H5CH2OH_0} =\frac{5.50x10^{-3}M}{5.55x10^{-3}M} =0.99$

Best regards.

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3 years ago

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Shelton measures a temperature of a solution to be 20O degrees C and stirs 5 grams of a substance into the solution. this substa

gogolik [260]

Answer:

did u ever get an answer??

Explanation:

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3 years ago

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If a sample of cork has a mass of 2.88 g and a volume of 12.0 mL, what is the density of the cork? Show your work.

PilotLPTM [1.2K]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

<h3> $density = \frac{mass}{volume}$ </h3>

From the question

mass of cork = 2.88 g

volume = 12 mL

The density is

$density = \frac{2.88}{12}$

We have the final answer as

0.24 g/mL

Hope this helps you

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3 years ago

Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi

professor190 [17]

Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity of COCl2 = 1.6 M

Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

The initial concentration of CO and Cl2 = 0M

There will react xM of COCl2

Since the mole ratio is 1:1

The final concentration of CO and Cl2 will be X M

The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc= [CO] *[Cl2] / [COCl2] = 8.33*10^-4

Kc = X*X / 1.6-X = 8.33 * 10^-4

8.33 * 10^-4 = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl2]

[COCl2] = 1.6 - 0.0361 = 1.5639 M

To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

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3 years ago