Factor f(x)=x² + 4x +3

After distilling your crude methyl benzoate, you set aside 5.12 grams of the purified ester. You then prepare the grignard reage

marysya [2.9K]

Answer:

Percent yield is 54%

Explanation:

The Grignard reaction is:

Mg + bromobenzene → phenylmagnesium bromide

Moles of Mg are:

2,3g×(1mol/24.3g) = 0.095 moles Mg.

Moles of bromobenzene are:

9,45mL×(1.495g/1mL)×(1mol/157.01g)= 0.0900 of bromobenzene.

The limiting reactant is bromobenzene. That means moles of phenylmagnesium bromide are 0.0900 moles.

To produce triphenyl carbinol you require:

2 phenylmagnesium bromide + methyl benzoate → triphenyl carbinol

Moles of methyl benzoate are:

5.12g×(1mol/136,15g) = 0.0376 moles of methyl benzoate.

The complete reaction of 0.0376 moles of methyl benzoate requires:

0.0376 moles of methyl benzoate× $\frac{2mol PhenylmagnesiumBromide}{1molMethylBenzoate}$ = 0.0752 moles of phenylmagnesium bromide. As you have 0.900 moles of phenylmagnesium bromide, limiting reagent is Methyl benzoate and moles of triphenyl carbinol are 0.0376. In grams:

0.0376 moles of triphenyl carbinol×(260.33g/mol) = 9,79g of triphenyl carbinol -This is the teorethical yield-

Percent yield is the ratio of actual yield to the theoretical yield. That is:

5,3g / 9,79g ×100 = 54%

I hope it helps!

3 0

3 years ago

What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen? A. C3H4N B. C2

Ierofanga [76]

Answer:

A. C₃H₄N

Explanation:

Firstly, we need to calculate the no. of moles of C, H, and N using the relation:

no. of moles = mass/molar mass.

∴ no. of moles of C = mass/molar mass = (90.0 g)/(12.0 g/mol) = 7.5 mol.

∴ no. of moles of H = mass/molar mass = (11.0 g)/(1.0 g/mol) = 11.0 mol.

∴ no. of moles of N = mass/molar mass = (35.0 g)/(14.0 g/mol) = 2.5 mol.

We should get the mole ratio of each atom by dividing by the lowest no. of moles (2.5 mol of N).

∴ the mole ratio of C: H: N = (7.5 mol/2.5 mol): (11.0 mol/2.5 mol): (2.5 mol/2.5 mol) = (3: 4.4: 1) ≅ (3: 4: 1).

So, the empirical formula is: A. C₃H₄N.

3 0

4 years ago

HOW DO THE FOLLOWING COMPARE IN THE AMOUNT OF ALCOHOL THEY CONTAIN: 12 OZ. BEER(5% ALCOHOL), 12 OZ. WINE COOLER(5% ALCOHOL), 1 1

Pavlova-9 [17]

The amount of alcohol contained in each of the listed beverages can be compared as follows; 1/2 oz of 80 proof liquor > 5 oz of wine (12% alcohol) > 12 oz of wine cooler (5%alcohol) = 12 oz of beer (5%alcohol) .

A drink that contains alcohol must be an intoxicating beverage. The extent of intoxication of an alcoholic beverage depends on the amount of alcohol that the beverage contains. There are various types of alcoholic beverages as listed in the question.

The amount of alcohol contained in each of the listed beverages can be compared as follows; 1/2 oz of 80 proof liquor > 5 oz of wine (12% alcohol) > 12 oz of wine cooler (5%alcohol) = 12 oz of beer (5%alcohol) .

Learn more about alcoholic beverage: brainly.com/question/6967136

8 0

3 years ago

Can you look people up on brainly

jasenka [17]

I think yes why?
LMFOAOOA

7 0

3 years ago

What advice would you give to a person who handles hydrogen and oxygen in their workplace?I think I have an idea of what advice

finlep [7]

Regard the principle of utilization of two gas.

Make a consistent control of hardware containing gas.

Make a consistent control of weight diminishing valves giving gas.

No smoking zone.

3 0

3 years ago

Factorf(x)=x² + 4x +3​

Factorf(x)=x² + 4x +3