INTERmolecular forces (such as dipoles and London dispersion forces).
The actually compound isn't changing (it's still H2O in solid or liquid form), so INTRAmolecular bonds aren't being affected. It's just the strength of attraction between separate molecules that is weakening.
Explanation:
here is the answer. Feel free to ask for more chem help
Answer:
45.78 g NaClO
Explanation:
The reaction that takes place is:
- 2NaOH + Cl₂ → NaCl + NaClO + H₂O
In order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.
We <u>calculate the moles of NaClO formed</u>, from the limiting reactant:
- 1.23 mol NaOH *
= 0.615 mol NaClO
Finally we <u>convert NaClO moles to grams</u>, using its <em>molecular weight</em>:
- 0.615 mol NaClO * 74.44 g/mol = 45.78 g NaClO
Molality of C2H5OH is 1.1.27m.
What is Molality?
Molality is no.of moles present in One Kg solution .
Molality is represented by m
m= no.of moles/ weigt of solution in kg
Given is Molarity= 51.30M
molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml
Density=m/V
V = 107 ml
Molarity= no of moles/ Volume
51.5×46×107= x × 1000
weight of C2H5OH = 27.7g
molality = 27.7/1000××46
m= 1.27m
to learn more about Molality click brainly.com/question/20380670
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Pressure of argon = 546.8 kPa
Conversion factor: 1 atm = 101.325 kPa
Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm
Moles of argon = 15.82
Volume of argon = 75.0 L
According to Ideal gas law,
PV = nRT
where P is the pressure, V is the volume , n is the number of moles, R is the universal gas constant, and T is the temperature
T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)
T = 311.82 K
Hence the temperature of the canister is 311.82 K.
