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3 years ago

What observation do you expect if you react an acid and a base?

1 answer:

8 0

"They react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water."

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Who were the scientists who won the nobel prize for the atomic model?

AleksAgata [21]

Answer:

Here's what I find.

Explanation:

Many scientists contributed to our model of the atom.

Among those who received the Nobel Prize for their work are:

1906 — J.J. Thomson — discovery of the electron

1908 — Ernest Rutherford — nuclear model of the atom

1922 — Niels Bohr — planetary model of the atom

1922 — Albert Einstein — quantum mechanical model of the atom

1935 — James Chadwick — discovery of the neutron

4 0

3 years ago

Plz help, I will give brainliest.

baherus [9]

Answer: The value of $K_c$ is 2

Explanation:

Moles of $N_2O_4$ = 1.0 mole

Volume of solution = 1.00 L

Initial concentration of $N_2O_4$ = $\frac{1.0mol}{1.00L}=1.0M$

Equilibrium concentration of $NO_2$ = $\frac{1.0mol}{1.00L}=1.0M$

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial conc. 1.0 M 0 M

At eqm. conc. (1.0-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

$K_c=\frac{(1.0)^2}{(1.0-0.5)}$

$K_c=2$

Thus the value of $K_c$ is 2

4 0

3 years ago

What is the name for the compound li2so4

Mariana [72]

Answer:

Explanation:

Lithium Sulphate

6 0

3 years ago

Read 2 more answers

Initial mass of triphenyl methanol in g = 0.220g Initial volume of 33% HBr solution in ml = 0.60 ml Find mas of triphenyl bromid

tensa zangetsu [6.8K]

Answer:

0.792g of triphenyl bromide are produced.

Explanation:

The reaction of triphenyl methanol with HBr is:

triphenyl methanol + HBr → Triphenyl bromide.

Reaction (1:1), 1 mole of HBr reacts per mole of triphenyl methanol.

To know the mass of triphenyl bromide assuming a theoretical yield (Yield 100%) we need to find first limiting reactant:

Moles triphenyl methanol (Molar mass: 260.33g/mol) =

0.220g × (1mol / 260.33g) = 8.45x10⁻³ moles Triphenyl methanol

Moles HBr (Molar mass: 80.91g/mol; 33%=33g HBr/100mL) =

0.60mL ₓ (33g / 100mL) ₓ (1mol / 80.91g) = 2.45x10⁻³ moles HBr

As amount of moles of HBr is lower than moles of triphenyl methanol, HBr is limiting reactant.

As HBr is limiting reactant, moles produced of triphenyl bromide = moles HBr = 2.45x10⁻³ moles

As molar mass of triphenyl bromide is 323.2g/mol, mass of triphenyl bromide is:

2.45x10⁻³ moles × (323.2g / mol) =

<h3>0.792g of triphenyl bromide are produced.</h3>

5 0

3 years ago

A bottle of 2 moles of an ideal diatomic gas experiences a temperature increase of 50.0K at constant volume. (a) Find the increa

andre [41]

Answer:

Explanation:

a) For diatomic gas: Translational motion = 3 and rotational motion = 2

∴ Total (internal energy) = 3 + 2 = 5

b) Translational + Rotational + Vibrational = 3 + 2 + 1 = 6

c) Linear molecule

i) Non linear molecule

ii) Monatomic molecule

5 0

3 years ago