Answer : The volume of
in Reaction 1 = 240.45 ml
The volume of
in Reaction 2 = 480.89 ml
Solution : Given,
Temperature =
(
)
Pressure = 0.900 atm
The mass of
= 1 gram
Molar mass of
= 84.007 g/mole
The given reactions are,
Reaction 1 : 
Reaction 2 : 
- <u>Calculation for Reaction 1 :</u>
First we have to calculate the moles of
.
Moles of
= 
From the Reaction 1, we conclude that
2 moles of
gives 1 mole of 
0.0119 moles of
gives
of 
Using ideal gas equation :

where,
P = pressure of gas
V = volume of gas
n = Number of moles
T = temperature of gas
R = gas constant = 0.0821 L atm/mole K
Now put all the given values in ideal gas law, we get the volume of 

The volume of
in Reaction 1 is 240.45 ml
- <u>Calculation for Reaction 2 :</u>
The moles of
= 0.0119 moles
From the Reaction 2, we conclude that
1 moles of
gives 1 mole of 
So, the moles of
= the moles of
= 0.0119 moles
Using ideal gas equation,

Now put all the given values in ideal gas law, we get the volume of 

The volume of
in Reaction 2 is 480.89 ml