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3 years ago

I NEED THIS ASAP Someone please help me

Chemistry

2 answers:

IceJOKER [234]3 years ago

8 0

Answer:

B. Four moles of water were produced from this reaction.

Explanation:

I took the test and got it correct

marysya [2.9K]3 years ago

6 0

Answer:

the answer is B

Explanation:

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Does anyone know this awnser please help

Vadim26 [7]

the answer is A bruddah.

5 0

3 years ago

The most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to

diamong [38]

Answer:

0.693kg of CuFeS2 is needed to produce 240 grams of Cu.

Explanation:

In 1 mole of CuFeS2 is associated 1 mole of Cu.

Molar mass of CuFeS2 = 183.5 g/mol

Molar mass of Cu = 63.5g/mol

No of moles of copper present in 240g of chalcopyrite = 240/63.5 = 3.779moles

we know

1 mole of Cu → 1 mole of CuFeS2

in 3.779 moles of Cu → 3.779 moles of CuFeS2

3.779 moles of CuFeS2 = 3.779 * 183.5 = 693.45grams

CuFeS2 in kg = 0.693kg

5 0

3 years ago

What is an atom? A- the smallest particle of an element. B- the negatively charged particle found in a cloud. C- the densely pac

cestrela7 [59]

Answer:

Explanation:

it is the most basic unit of matter

5 0

3 years ago

Read 2 more answers

The ionization energies (kJ/mol) of hydrogen, nitrogen, sodium, chlorine, and fluorine are 1,312, 1,402, 496, 1,256, and 1,681,

Norma-Jean [14]

Answer: Sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.

More is the value of ionization energy more it is difficult to remove an electron. Therefore, lesser is the reactivity of element.

Hence, we can conclude that sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

6 0

3 years ago

Classify the possible combinations of signs for a reaction's ΔH and ΔS values by the resulting spontaneity

FinnZ [79.3K]

Answer :

(A) ΔH is positive and ΔS is negative → (2) Spontaneous in reverse at all temperatures

(B) ΔH is positive and ΔS is positive → (3) Spontaneous as written above a certain temperature

(C) ΔH is negative and ΔS is positive → (1) Spontaneous as written at all temperatures

(D) ΔH negative and ΔS is negative → (4) Spontaneous as written below a certain temperature

Explanation :

According to Gibb's equation:

$\Delta G=\Delta H-T\Delta S$

$\Delta G$ = Gibbs free energy

$\Delta H$ = enthalpy change

$\Delta S$ = entropy change

T = temperature in Kelvin

As we know that:

$\Delta G$ = +ve, reaction is non spontaneous

$\Delta G$ = -ve, reaction is spontaneous

$\Delta G$ = 0, reaction is in equilibrium

(A) ΔH is positive and ΔS is negative.

$\Delta G=\Delta H-T\Delta S$

$\Delta G=(+ve)-T(-ve)$

$\Delta G=(+ve)$

The reaction is non-spontaneous at all temperatures or spontaneous in reverse at all temperatures.

(B) ΔH is positive and ΔS is positive.

$\Delta G=\Delta H-T\Delta S$

$\Delta G=(+ve)-T(+ve)$

$\Delta G=(+ve)$ (at low temperature) (non-spontaneous)

$\Delta G=(-ve)$ (at high temperature) (spontaneous)

The reaction is spontaneous as written above a certain temperature.

(C) ΔH is negative and ΔS is positive.

$\Delta G=\Delta H-T\Delta S$

$\Delta G=(-ve)-T(+ve)$

$\Delta G=(-ve)$

The reaction is spontaneous as written at all temperatures

(D) ΔH is negative and ΔS is negative.

$\Delta G=\Delta H-T\Delta S$

$\Delta G=(-ve)-T(-ve)$

$\Delta G=(+ve)$ (at high temperature) (non-spontaneous)

$\Delta G=(-ve)$ (at low temperature) (spontaneous)

The reaction is spontaneous as written below a certain temperature.

4 0

3 years ago