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Troyanec [42]
3 years ago
6

If a truck has 40,500 kg*m/s momentum and is moving with a velocity of 90 M/S, what is the trucks mass?

Physics
1 answer:
adoni [48]3 years ago
6 0

Answer: 450 kg

Explanation: p=mv

m= p/v

m=40500/90

m=450kg

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Un cuerpo se lanza verticalmente hacia arriba con una velocidad de 13 m/s. ¿Cuánto tiempo tarda en alcanzar la altura máxima? a)
Elena L [17]

Answer:

D. 1.33 segundos.

Explanation:

El cuerpo es experimenta un movimiento en caída libre al modificarse su velocidad por efecto de la gravitación terrestre. Este cuerpo alcanza instantáneamente el reposo cuando se encuentra a su altura máxima, el tiempo puede obtenerse sabiendo la aceleración y las velocidades incial y final a partir de la siguiente ecuación cinemática:

v = v_{o}+g\cdot t

Donde:

v - Velocidad final del cuerpo, medida en metros por segundo.

v_{o} - Velocidad inicial del cuerpo, medida en metros por segundo.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

t - Tiempo, medido en segundos.

Ahora se despeja el tiempo:

t = \frac{v-v_{o}}{g}

Si v_{o} = 13\,\frac{m}{s}, v=0\,\frac{m}{s} y g = -9.807\,\frac{m}{s^{2}}, entonces:

t = \frac{0\,\frac{m}{s}-13\,\frac{m}{s}}{-9.807\,\frac{m}{s^{2}} }

t = 1.326\,s

Por ende, la respuesta correcta es D.

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3 years ago
What is the magnitude of the force acting on a spring with a spring constant of 275 N/m that is stretched 14.3 cm?
Travka [436]
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g100num [7]

Answer:

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(c) - 570.75 J

(d) 0 J, 0 J

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distance, s = 7 m

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F = 0.26 x m x g = 0.26 x 32 x 9.8 = 81.54 N

(b) The work done on the crate

W = F x s = 81.54 x 7 = 570.75 J

(c) Work done by the friction

W' = - W = - 570.75 J

(d) Work done by the normal force

W'' = m g cos 90 = 0 J

Work done by the gravity

Wg = m g cos 90 = 0 J

(e) The total work done is

Wnet = W + W' + W'' + Wg = 570.75 - 570.75 + 0 = 0 J  

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Answer:

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