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3241004551 [841]
3 years ago
10

If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?

Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

v = -6m/s

Explanation:

x=4-12t+3t^2

\frac{dx}{dt}=-12+6t

For t = 1:

\frac{dx}{dt}=-6

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Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

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To answer this part, we re-arrange the previous equation as follows:

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Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

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this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

a \propto F

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

#LearnwithBrainly

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Igoryamba

Answer:

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