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3 years ago

8

H twice differentiable [-1, 1] show h(1/nz^n is holomorphic h(0 = h'(0 = 0

1 answer:

jok3333 [9.3K]3 years ago

7 0

What are the choices

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Find the derivative of y=sin^(2)(x)cos^(2)(x)

wariber [46]

$sin^{2}x \ cos^{2} x= \frac{1}{2} (1-cos2x) \times \frac{1}{2} (1+cos2x) \\ = \frac{1}{4} (1- cos^{2} 2x) \\ = \frac{1}{4} ( sin^{2} 2x +cos^{2} 2x- cos^{2} 2x) \\ = \frac{1}{4} ( sin^{2} 2x) \\ = \frac{1}{4} ( \frac{1}{2} (1-cos2(2x))) \\ = \frac{1}{8} (1-cos4x) \\ \frac{d}{dx} (sin^{2}x \ cos^{2} x)= \frac{1}{8} \frac{d}{dx} (1-cos4x) \\ = \frac{1}{8} [-4(-sin4x) \\ \frac{1}{2} sin4x$

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2 years ago

Suppose you are given two quadrilaterals, ABCD EFGH. If the similarity ratio of ABCD to EFGH is 4:3, and if EH = 60, find AD.

Sophie [7]

4/3 = AD/EH (similarity)

hence, AD= EH*4/3=60*4/3=80

so, 80

4 0

3 years ago

Help me on this question please

mario62 [17]

Step-by-step explanation:

lawn = garden - veg - flower

=(14*10) - ((5+7)/2 *10) - (0.5*3*8)

= 140 - 60 - 12

= 68 Squared meters

4 0

2 years ago

Karl is thinking of holding a mini lottery to raise money.

Katena32 [7]

Answer:

ok

Step-by-step explanation:

5 0

2 years ago

A man that is 6 feet tall casts a shadow 5 feet long. At the same time, a lamppost beside the man casts a shadow 25 feet long. H

Montano1993 [528]

Answer:

The answer to your question is: L = 30 ft

Step-by-step explanation:

Data

man = 6 ft

man shadow = 5 ft

lamppost shadow = 25 ft

lamppost height = ? = L

Process

$\frac{6}{5} = \frac{L}{25}$

$L = \frac{6 x 25}{5}$

$L = \frac{150}{5}$

L = 30 ft

5 0

3 years ago