In alternate leaf patterns, how many leaves are produced at each node?
Answer: One
Answer:
Explanation:
Possible gametes of OOTt are OT and Ot.
Possible gametes of OoTt are OT, Ot, oT, and ot.
The punnet square is shown in the attached figure.
As per the punnet square there are six genotypes and two phenotyes.
The genotypes with ratios are:
OOTT = 2/16
OOTt = 4/16
OOtt = 2/16
Oott = 2/16
OoTT = 2/16
OoTt = 4/16
The two phenotypes "orange with tall stems" and "orange with small stems" will be present in 12:4 i.e. 3:1.
Answer:
Explanation:
the crossing of the F1 generation will result in the following;
tall green purple terminal : tall yellow purple terminal : dwarf green purple terminal : dwarf yellow purple terminal : tall green white terminal : tall yellow white terminal : dwarf green white terminal : dwarf yellow white terminal : tall green purple axial : tall yellow purple axial : dwarf green purple axial : dwarf yellow purple axial : tall green white axial : tall yellow white axial : dwarf green white axial : dwarf yellow white axial.
there is only one dwarf, yellow pod, white axial flower in the F2
We can confirm that the probability of a student who completed the assignment receiving a passing grade is above 90%.
<h3>How can we calculate this probability?</h3>
We can arrive at this number with the information given to us. We are told that of the 16 students who successfully completed the assignment, 15 received passing grades. By dividing this number we can find the percentage of these students that passed, and this serves as the probability, which results in roughly 93%.
Therefore, we can confirm that the probability of a student who completed the assignment receiving a passing grade is above 90%.
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