Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e .
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum
The velocity of the other fragment immediately following the explosion is v .
<span>The gain in potential energy is 600*2 = 1200 J, and this is the minimum required work that would be required in a frictionless situation. The work that actually has to be done is F*X = 300*5 = 1500 J. The efficiency is therefore 1200/1500 = 80%</span>
<span>when you say a=4.02 i am going to acceleration in m/s^2.
If the acceleration is 4.02 then you take the integral to find the speed.
speed=4.02 t where t is time in seconds.
[4.02(0)+4.02(3.11)]/2=6.2511
[4.02(3.11)+4.02(6.22)]/2=18.7533</span>
Answer:
a) actual reading=2mm+(0.1×8)=2.8 mm=0.28 cm
b)actual reading=5 mm+(0.1×7)=5.7mm=0.57 cm
c)actual reading=9 mm=0.9 cm
d)actual reading=0 mm+(0.1×7)=0.7 mm=0.07 cm
e)actual reading=19 mm+(0.1×9)=19.9 mm=1.99 cm
f)actual reading=15 mm+(0.1×3)=15.3 mm=1.53 cm
g)actual reading=11 mm(0.1×5)=11.5 mm=1.15 cm